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natima [27]
2 years ago
6

Ummm how do you do this two questions?

Mathematics
1 answer:
guajiro [1.7K]2 years ago
8 0

Answer:

Here are the formulae you need. Just plug in the values you have and you will get your answers.

Area of a triangle: 1/2*base*height

Volume of a rectangular prism: length*width*height

Volume of a cylinder: pi*r^2*height

Step-by-step explanation:

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Can someone please help with this i don’t know how to do it 85points
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Answer:

Step-by-step explanation:

You can find the area by cutting it across in the middle into a trapezoid and a rectangle.

The trapezoid will have:

height = 10-4 = 6ft

top = 9-6 = 3ft

bottom = 8ft

So its area = 1/2*(3+8)*6 = 33 ft^2

The rectangle will have:

length = 10ft

width = 6ft

So its area = 10*6 = 60 ft^2

Total area = 60+33 = 93 ft^2

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USPshnik [31]
The owners profit is 252 dollars 

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3 years ago
Divide: 83.5 ÷ 6.25 The first step in solving 83.5 ÷ 6.25 is to multiply the divisor and dividend by . The new division problem
kherson [118]

Answer:

The first step in solving 83.5 ÷ 6.25  is to multiply the divisor and dividend by  

[✔ 100 ]

sorry idk the answer for the second one :(

Step-by-step explanation:

7 0
3 years ago
An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (
oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

y^2=1-3x^2

3x^2+y^2=1

\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1

therefore it is a vertical ellipse

thus a=1

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eccentricity of Ellipse

e^2=1-\frac{b^2}{a^2}

e^2=1-\frac{1}{(\sqrt{3})^2}

e^2=1-\frac{1}{3}

e^2=\frac{2}{3}

e=\sqrt{\frac{2}{3}}

Focii are (0,ae) and (0,-ae)

ae=1\times \sqrt{\frac{2}{3}}

thus focii are (0,\sqrt{\frac{2}{3}}) & (0,-\sqrt{\frac{2}{3}})

(b) Length of major axis =2a=2\times 1

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