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natima [27]
2 years ago
6

Ummm how do you do this two questions?

Mathematics
1 answer:
guajiro [1.7K]2 years ago
8 0

Answer:

Here are the formulae you need. Just plug in the values you have and you will get your answers.

Area of a triangle: 1/2*base*height

Volume of a rectangular prism: length*width*height

Volume of a cylinder: pi*r^2*height

Step-by-step explanation:

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bezimeni [28]

Answer:

B. 6.2

Step-by-step explanation:

The calculation is done by hand and verified by a TI-84 calculator.

8 0
3 years ago
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True or false?
Firdavs [7]

Answer:

b

Step-by-step explanation:

brainliest pls

8 0
3 years ago
Find the surface area of the right rectangular prism shown below. units²
faust18 [17]

Answer:

67 units^2

Step-by-step explanation:

The surface area of the prism is found by

SA = 2 ( lw+lh + wh)

     = 2 ( 5*1.5+ 4*1.5 + 5*4)

     = 2 ( 7.5+6+20)

     = 2 (33.5)

    = 67

5 0
3 years ago
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The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
What is the point slope form of the points?
Darina [25.2K]

the equation of a line in point-slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

to calculate m use the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 4, - 1) and (x₂, y₂) = (1 1/2, 2 )

m = \frac{2+1}{11/2+4} = \frac{3}{5 1/2} = \frac{6}{11}

using (a, b) = (- 4, - 1), then

y + 1 = \frac{6}{11}(x + 4)


6 0
3 years ago
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