Question

What is the equation of the line which passes through (-0.5,-5) and (2,5)

Answer 1

Answer:

$y = 4x-3$

Step-by-step explanation:

The coordinates are (-0.5,-5) and (2,5)

Finding the slope, m:

=> Slope = $\frac{rise}{run}$

=> Slope = $\frac{5+5}{2+0.5}$

=> Slope = $\frac{10}{2.5}$

=> Slope = 4

Now, y-intercept, b:

Taking any of the two coordinate and putting it in the slope intercept equation:

=> Point = (x,y) = (2,5)

So, x = 2, y = 5

=> $y = mx+b$

=> 5 = (4)(2) + b

=> 5 = 8 + b

=> b = 5-8

=> b = -3

Now, Putting in slope intercept equation:

=> $y = mx+b$

=> $y = 4x-3$

Answer 2

Gradient (m) = x2-x1

y2-y1

considering

y1 = -5 y2 = 5

x1 = -0.5. x2 = 2

m = 2-(-0.5)

5-(-5)

m = 5.5

10

m = 11. = 0.55

20

equation of a line is given by

y-y1 = m+(x-x1)

y-(-5) =0.55 + {x-(-0.5)}

y+5 = 0.55 + x+0.5

making y the subject

y = 0.55 +0.5 -5 + x

y = -3.95 + x