All categories

3 years ago

Find the surface area of the right square pyramid. Round your answer to the nearest hundredth.

Mathematics

1 answer:

jekas [21]3 years ago

7 0

Answer:

A. 176

Step-by-step explanation: First, to find the surface area to each triangle, you multiply the base times the height by 1/2. It is 28 for each triangle. Multiply that by 4, and you get 112. Then, the surface area of the square on bottom is 64. When added together, you get 176. No rounding needed. Hope it helped and is correct!

You might be interested in

60>5(6-2x) ok help me so I can get an answer

Dima020 [189]

Inequalities are used to represent unequal expressions

The solution to the inequality is: $x > -3$

<h3>How to determine the inequality solution</h3>

The inequality is given as:

60>5(6-2x)

Rewrite the inequality properly as:

$60>5(6-2x)$

Divide both sides of the inequality by 5

$12>6-2x$

Subtract 6 from both sides of the inequality

$6>-2x$

Divide both sides of the inequality by -2

$-3Rewrite the inequality as[tex]x > -3$

Hence, the solution to the inequality is: $x > -3$

Read more about inequalities at:

brainly.com/question/11234618

5 0

2 years ago

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got: