Margaret earned a scored of 38/40 on her test. What is the decimal expansion of the score she received

Six Flags Amusement Park has found that 3/5 of its customers ride the Colossus roller coaster. Of these, 1/4 ride it again. What

QveST [7]

Answer:

The answer is B. 3/20

Step-by-step explanation:

That will be 1/4 of 3/5

3/5 × 1/4

3/20

3 0

3 years ago

Calculate 85% of 2 500m

vaieri [72.5K]

Answer:

Step-by-step explanation:

85% of 2500 m

= 85/100 × 2500 = 2125 m

hope this helps

plz mark it as brainliest!!!!!!

6 0

3 years ago

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[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So

Fynjy0 [20]

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

Part 1: The data points given are 0, 0, 1/4, 1/2, 1/2, 1, 1, 1, 5/4, 2, and 2.

The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

Hope this helps!

5 0

3 years ago

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For fun question

ZanzabumX [31]

Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

$f(63.97)\approxf'(64)(63.97-64)+f(64)$
$\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375$

Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...

4 0

3 years ago

Which properties of equality justify steps b and d?

7nadin3 [17]

C. Subtraction Property of Equality; Multiplication Property of Equality

For the first one, you are subtracting 7 from both sides (step b), to help isolate the y

since you are both subtracting, and "both sides" (meaning there is a equal sign) it is Subtraction Property of Equality.

For the second one, you are multiplying 2 from both sides (step d), to help isolate the y

since you are multiplying, and "both sides" (meaning there is a equal sign), it is Multiplication Property of Equality

hope this helps

4 0

3 years ago

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