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-Dominant- [34]
3 years ago
5

Will give brainliest pls answer correctly

Mathematics
2 answers:
Minchanka [31]3 years ago
5 0
The answer is
R=65-60p
r=5(13-12p)
Rufina [12.5K]3 years ago
5 0

Answer: r = 5(13-12p)

Step-by-step explanation:

To factor, take out the GCF (the largest number that can be taken out of the equation to leave all numbers as whole numbers). In this case, the largest number that can be taken out of the equation is 5.

Take 5 out from the equation and put it outside of the parenthesis (a factor). Divide 65 and -60p by 5 to find the value of the numbers within the parenthesis.

After doing so, you will have your equation factored.

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Janie and Jasmine are playing three games at an arcade. Each of the games requires either 2, 3, or 4 tokens. The girls plan to p
DENIUS [597]
I think the answer would be -12 maybe
3 0
4 years ago
Helppppppppppppppppppppppp
PolarNik [594]
Answer:
The second choice is the correct one

Explanation:
(2x+3)^2 + 8(2x+3) + 11 = 0
To use the u substitution, we will assume that:
2x + 3 = u

Substitute with this in the given expression, we will get:
u^2 + 8u + 11 = 0 

The general form of the second degree equation is:
ax^2 + bx + c = 0

Comparing the expression we reached with the general one, we will find that:
a = 1
b = 8
c = 11

The roots can be found using the rule found in the attached picture.
This means that, for the given expression:
u = -4 ± √5 

Now, we have:
u = 2x+3
This means that:
at u = -4 + √5 
2x + 3 = -4 + √5 
2x = -7 + √5
x = (-7 + √5) / 2

at u = -4 - √5 
2x + 3 = -4 - √5 
2x = -7 - √5
x = (-7 - √5) / 2

This means that, for the given expression:
x = (-7 ± √5 ) / 2

Hope this helps :)

7 0
3 years ago
Read 2 more answers
Help me to solve this equations please
egoroff_w [7]

Answer:

Shown Below

Step-by-step explanation:

Shown Below

1. 3^x=81 3^4=81 x=4

2. 169^x=13 x= 1/2

3. 5^x= 1/5 x= -1 (inverse)

4. 0.5^x=4 x= -2

5. 2^x= 1/2 x =-1

5 0
3 years ago
How many collections of six positive, odd integers have a sum of 18? Note that 1 + 1 + 1 + 3 + 3 + 9 and 9 + 1 + 3 + 1 + 3 + 1 a
san4es73 [151]

Answer:

  11

Step-by-step explanation:

Suitable software can generate these collections. They are ...

{13,1,1,1,1,1}, {11,3,1,1,1,1}, {9,5,1,1,1,1}, {9,3,3,1,1,1},

{7,7,1,1,1,1}, {7,5,3,1,1,1}, {7,3,3,3,1,1}, {5,5,5,1,1,1},

{5,5,3,3,1,1}, {5,3,3,3,3,1}, {3,3,3,3,3,3}}

5 0
3 years ago
I need help, please! Thanks!
dalvyx [7]
The first I think is 4 units square and the second is 21 units square
8 0
3 years ago
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