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snow_lady [41]
2 years ago
6

The ratio of teachers to students in a particular school is 5 to 26. The ratio of female students to the total number of student

s is 6 to 13. If there are 72 female students, how many teachers are there?
Mathematics
1 answer:
mixer [17]2 years ago
5 0

Answer:

The answer is is 30 teachers

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Simplify the expression<br> (-3+4k) - (-2+ 7k)
DedPeter [7]

Answer: −1−3k

Step-by-step explanation:

Distribute:

(−3+4k)−1(−2+7k)

(-3+4k)+{2-7k}

Eliminate redundant parentheses:

(−3+4k)+2−7k

-3+4k+2-7k

Add the numbers:

−3+4k+2−7k

−1+4k−7k

Add the same term to both sides of the equation:

−1+4k−7k

−1−3k

4 0
3 years ago
Can anyone help?
SVEN [57.7K]

For the equation (2k + 1)x² + 2x = 10x - 6 to have two real and equal roots, the value of k = 5/6.

Since the equation is (2k + 1)x² + 2x = 10x - 6, we collect subtract 10x from both sides and add 6 to both sides.

So, we have (2k + 1)x² + 2x - 10x + 6 = 10x - 6 - 10x + 6

(2k + 1)x² - 8x + 6 = 0

For the equation, (2k + 1)x² + 2x = 10x - 6 to have two real and equal roots, this new equation (2k + 1)x² - 8x + 6 = 0 must also have two real and equal roots.

For the equation to have two real and equal roots, its discriminant, D = 0.

D = b² - 4ac where b = -8, a = 2k + 1 and c = 6.

So, D =  b² - 4ac

D =  (-8)² - 4 × (2k + 1) × 6 = 0

64 - 24(2k + 1) = 0

Dividing through by 8, we have

8 - 3(2k + 1) = 0

Expanding the bracket, we have

8 - 6k - 3 = 0

Collecting like terms, we have

-6k + 5 = 0

Subtracting 5 from both sides, we have

-6k = -5

Dividing through by -6, we have

k = -5/-6

k = 5/6

So, for the equation (2k + 1)x² + 2x = 10x - 6 to have two real and equal roots, the value of k = 5/6.

Learn more about quadratic equations here:

brainly.com/question/18162688

4 0
3 years ago
A car depreciated $1000 the first year it was owned and driven. In years 2 and
Sidana [21]

AAnswer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Log3(7x) Use the Laws of Logarithms to expand the expression.
Bingel [31]
Log3(7) + log3(x)
Terms that are multiplied inside one log become added when you separate them where each term gets its own log.
7 0
3 years ago
Write three ordered pairs for direct variation relationship where y= 12 when x= 16
Kruka [31]

Ordered pairs that work for this direct variation are (4, 3), (8, 6) and (12, 9).

In order to find these, we must first find the value of the direct variation coefficient. We can do that using the base equation y = kx and then by plugging in to find k.

y = kx

12 = k(16)

3/4 = k

Now that we have k, we can model the equation as y = 3/4x. We can also find any number of ordered pairs by using the x value and finding the y value. All of the above answers work.

3 0
3 years ago
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