All categories

2 years ago

Jackson is buying a new TV for $650. He will also be

Mathematics

2 answers:

Zina [86]2 years ago

8 0

Answer:

his total bill would be 698.75

Step-by-step explanation

you only did half of the problem lol.

48.75 is just the sales tax. to get the total bill, you need to add 650 to 48.75 because 650 is the actual price of the TV

hope this helps :)

Elenna [48]2 years ago

8 0

Answer:

This is an percentage change question to calculate this, simply:

7.5% * 650 is 48.75 (You are correct here)

But the question

asks for) "Jackson' total bill) therefore its 48.75 + 650 = 698.75

Cheers! :)

You might be interested in

X+y+z=1<br> X-2y+3z=2<br> X+z-5=0

serious [3.7K]

x+y+z=1

x=1/(y+z)

1/(y+z)-2y+3z=2

1-2y²-2yz+3yz+3z²=2(y+z)

(1-2y²+yz+3z²)/2=y+z

z=(1-2y²+yz+3z²)/2 -y/1

z=(1-2y²+yz+3z²-2y)/2

8 0

3 years ago

HELP ME PLZ

zubka84 [21]

————————————-The answer is 3.78

6 0

2 years ago

Read 2 more answers

What is the solution to x3 = 64? A 4 B 8 C 16 D 21

dedylja [7]

Answer:

Option A

Step-by-step explanation:

I am assuming that '3' is an exponent.

$x^3=64\\\\\sqrt[3]{x}=\sqrt[3]{64}\\\\\boxed{x=4}$

Hope this helps.

6 0

2 years ago

Please help me thank you

Anna35 [415]

Answer:

b = 20 when a = 8.

Step-by-step explanation:

For this problem, we will simply plug the value of a=8 into the given equation for b, to find the value of b.

b = [ (a)^2 / 4 ] + 4

b = [ (8)^2 / 4 ] + 4

b = [ 64 / 4 ] + 4

b = [ 16 ] + 4

b = 20

Hence, when the value of a=8, then the value of b=20.

Cheers.

8 0

2 years ago

Read 2 more answers

In the figure, the perimeter of hexagon ABCDEF is approximately ___

blsea [12.9K]

Let
$F(-10,0) A(10,10) B(20,10) C(30,0) D(20,-10) E(10,-10)$
we know that
$FA=FE \\ AB=ED \\ BC=CD$

step 1
find distance FA
$dFA= \sqrt{ (y2-y1)^{2} +(x2-x1)^{2} } \\ dFA= \sqrt{ (10-0)^{2} +(10+10)^{2}$

$dFA= \sqrt{500} \\ dFA=22.36 units$

step 2
find distance AB
$dAB=20-10 \\ dAB=10 units$

step 3
find the distance BC
$dBC= \sqrt{ (y2-y1)^{2} +(x2-x1)^{2} }$
$dBC= \sqrt{ (0-10)^{2} +(30-20)^{2} }$
$dBC= \sqrt{200}$
$dBC=14.14 units$

step 4
find the perimeter
the perimeter is equal to
$P=2*[FA+AB+BC] \\ P=2*[22.36+10+14.14] \\ P=93 units$

step 5
find the area
the area is equal to
area triangle AFE+area rectangle ABDE+area triangle BDC

step 6
find the area of triangle AFE
$A1=20*20/2 \\ A1=200 units^{2}$

step 7
find the area of the rectangle ABDE
$A2=10*20 \\ A2=200 units^{2}$

step 8
find the area of the triangle BDC
$A3=20*10/2 \\ A3=150 units^{2}$
$Area Total=200+200+150 \\ Area Total=550 units^{2}$

8 0

2 years ago

Read 2 more answers