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Irina18 [472]
3 years ago
6

HAVE A NICE DAY WILL GIVE BRAINLST :)

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0

Answer:

DEF = 103

Step-by-step explanation:

brainlyist pls

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Find the value of x. 6 8 4 x
snow_tiger [21]
Answer:

3

Explanation:

4 is half of 8 on the right side, so that means X has to be half of 6, so it’s 3. Also, it couldn’t be 2 because it is too big, and it can’t be 4 because it isn’t the same length as the other 4, so it’s 3
8 0
3 years ago
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and
MrRissso [65]

Answer:

<h2>a) center (2, -3)</h2><h2>b) radius r = 3</h2><h2>c) in the attachment</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

(x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2

a) center (2, -3)

b) radius r = 3

c) in the attachment

4 0
3 years ago
Place the indicated product in the proper location on the grid.<br><br> За^2 x 2а^3​
AlekseyPX

Answer:

when i got the answer i got 12a^25

Step-by-step explanation:

i dont know if this helps

8 0
2 years ago
I can have multiple<br> different representations.<br> All 6 of my faces are<br> square.
Dafna11 [192]

Answer:

Find the area of the trapezoid below.

Step-by-step explanation:

5 0
3 years ago
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