Answer:
A. 5.16 s.
B. 5.66 s.
Step-by-step explanation:
A.
For a simple harmonic motion,
T = 2pi (sqrt * (l/g))
Given:
L1 = 3 cm
T1 = 4 s
L2 = 5 cm
T2 = ?
4 = 2pi*sqrt(3/g)
g = 7.4
At, L2,
T2 = 2pi*sqrt(5/7.4)
= 5.16 s.
B.
M1 = M1
M2 = 2*M1
For a simple harmonic motion,
T = 2pi (sqrt * (m/k))
4 = 2pi (sqrt * (M1/k))
M1/k = 0.405
Inputting the above values,
T2 = 2pi (sqrt * (2*M1/k))
= 2pi (sqrt * (2 * 0.405))
= 5.66 s.
Answer:
See possible solutions below.
Step-by-step explanation:
The statements are not given. But the following can be determined from the graph:
- More days recorded temperatures between 82 and 84 then other temperatures.
- The least number of days recorded temperatures between 88 and 90.
- The histogram is skewed to the right also known as positive skewed distribution.
- The mean and median will most likely be in the range of 82-84 temperatures. But the mean will be greater than the median.
Then put in some butter that will get you out
