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3 years ago

What is the answer? Please explain. (5x^2 -3) + (2x^2 - 3x^3)

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

(5x^2-3) +(2x^2-3x^3)

=3x^3+5x^2+2x^2-3

= 3x^3 +7x^2 -3

Step-by-step explanation:

hope this is correct cuz I'm not an expert...

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The wall street journal corporate perceptions study 2011 surveyed readers and asked how each rated the quality of management and

malfutka [58]

Answer:

Hello some parts of your question is missing below is the missing part

answer : A) p-value = 0.0019 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

Step-by-step explanation:

A) using a 0.05 level of significance and test for independence of the quality of management

Test statistic : $X^{2}$ ∑ ( Oi - Ei )^2 / Ei

= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03

p-value = 0.0019

Df = 4 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

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3 years ago

40% de cuanto son 32?

OlgaM077 [116]

Do not speak Spanish

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3 years ago

Read 2 more answers

What is mKNL?<br> Enter your answer in the box.

sergejj [24]

Answer:

102°

Step-by-step explanation:

As the vertically opposite angles are equal,

$5x+2={3(x+14)$

Now let's solve for x now

$5x+2=3(x+14)\\$

$5x+2=3x+42$

$5x-3x=42-2$

$2x=40$

$\frac{2x}{2} =\frac{40}{2}$

$x=20 \\$

Now let's find the value of KNL

$3(x+14)\\3(20+14)\\3*34\\102$

Hope this helps you.

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2 years ago

Compare -8 and 3. Which statement is not true?

siniylev [52]

Answer:

Step-by-step explanation:

it is the opposite of A, which is true, as |-8| = 8

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3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

$f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi$

Let us find first and second derivative for f(x)

$f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx$

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in $(0, \pi/2) U(\pi,3\pi/2)\\$

and decreasing in $(\pi/2, \pi)U(3\pi/2,2\pi)$

$x=\frac{\pi}{4}, \frac{3\pi}{4}$

$f"(\pi/4)$

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = $2sin \pi/4+2cos \pi/4 =2\sqrt{2}$

Minimum value = $2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}$

f"(x) =0 gives tanx =-1

$x= 3\pi/4, 7\pi/4$

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

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3 years ago