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Anuta_ua [19.1K]
3 years ago
8

Matthew has 30 Starbursts. Twelve are yellow and the rest are red. What is the ratio of yellow starbursts to red?

Mathematics
1 answer:
Damm [24]3 years ago
6 0

Answer is 2:3.

~Refer to the attachment for the solution.

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for what number value of lengthy and width will the rectangle have a area of 60 square yards and a perimeter of 38 yards
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The length is 4 and width 15. When multiplied the area equals 60 and when you add up all the sides the perimeter is also 38.
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Can someone PLZZZZ HELP!!!!
swat32

Answer:

The solution is:

Part A. \sqrt{5}^{\frac{7k}{3}}) which is sqrt(5)^7k/3[/tex]

Part B. k = 18/7

Step-by-step explanation:

Part A.

To solve this part, we're going two use THREE important properties of exponents:

1. (x^{n})^{m} = x^{nm}

2. \frac{x^{n}}{x^{m}} = x^{n-m}

3. \sqrt[n]{x^{m}} = x^{\frac{m}{n} }

Let's work the numerator using the properties 1, 2 and 3:

(\sqrt{5}^{3} )^{\frac{k}{9} } }  = (\sqrt{5}^{3\frac{k}{9}}) = (\sqrt{5}^{\frac{k}{3}})

Let's work the denominator using the properties 1, 2 and 3:

(\sqrt{5}^{6} )^{-\frac{k}{3} } }  = (\sqrt{5}^{6\frac{k}{3}}) = (\sqrt{5}^(2k))

Now dividing the numerator by the denominator:

\sqrt{5}^{\frac{k}{3}-(-2k)})=\sqrt{5}^{\frac{7k}{3}})

Part B

if 5^{\frac{3}{2} } 5^{\frac{3}{2}} = \sqrt{5}^{\frac{7k}{3}})

Then:

5^{3} = 5^{\frac{7k}{6}})

So \frac{7k}{6}} = 3

Solving for k, we have:

k = 18/7

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3 years ago
Question 31: Please help what is the cosine ratio of ∠X in the given triangle?
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Answer:

A

Step-by-step explanation:

\cos \: \angle X =  \frac{XY}{XZ}   =  \frac{5}{13}  \\

Hence, option A is the correct answer.

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Answer:

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b = ---------

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Step-by-step explanation:

We need to isolate b.  Starting from (g+l)b=n, we divide both sides by (g+l), obtaining

         n

b = ---------

      (g+l)

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4 years ago
Is 74 fl oz greater than less than or equal to 8cups
Mariana [72]
It is greater than because 74 fl. oz. is equal to 9.25 cups.
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