Multiply the fraction by 100%.
So is this just a free answer or?
Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
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▹ Answer
<em>6(1-r)</em>
▹ Step-by-Step Explanation
8 - (6r + 2)
8 - 2(3r + 1)
2(4 - (3r + 1))
2(4 - 3r - 1)
2(3 - 3r)
2 * 3(1 - r)
6(1 - r)
Hope this helps!
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