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natali 33 [55]
2 years ago
6

75, 75, 68, 11, 81, 69, 83, 13, 83 Calculate the range.

Mathematics
2 answers:
Fudgin [204]2 years ago
8 0

Answer:

72

Step-by-step explanation:

The greatest number in this set is 83

The smallest number is 11

We subtract the greatest from the smallest number in a set to find the range

83-11=72

Hoochie [10]2 years ago
7 0

Answer:

72 is the range

Step-by-step explanation:

Firstly, the range is the smallest number subtracted from the biggest one.

Secondly, find the biggest and smallest number. 11 and 83.

Thirdly, subtract. 83 - 11 = 72

Fourthly, have a wonderful day!

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miv72 [106K]

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<span><span>1) multiply both coordinates by scale factor<span>(<span><span>2⋅<span>12</span>,4⋅<span>12</span></span><span>2⋅<span>12</span>,4⋅<span>12</span></span></span>)</span></span><span>2)

2. Simplify(1,2)</span><span>3)

3. Graph(if required)<span> </span></span></span>
5 0
3 years ago
The graph of which function passes through the point ( 0,pi/2 )
inn [45]
<h2><u>Answer:</u></h2>

y = cos ^- 1 (x)

Step-by-step explanation:

The Function y = cos -1x = arccos x and its Graph: Since y = cos -1x is the inverse of the function y = cos x, the function y = cos -1x if and only if cos y = x. This leaves the range of the restricted function unchanged as [-1, 1].

6 0
3 years ago
Read 2 more answers
2 2/3 + 12 6/8 how do I work this
barxatty [35]

Answer:

\large\boxed{2\dfrac{2}{3}+12\dfrac{6}{8}=15\dfrac{5}{12}}

Step-by-step explanation:

2\dfrac{2}{3}+12\dfrac{6}{8}=2\dfrac{2}{3}+12\dfrac{6:2}{8:2}=2\dfrac{2}{3}+12\dfrac{3}{4}\\\\\text{Find}\ LCD:\\\\\text{List of multiples of 3:}\ 0,\ 3,\ 6,\ 9,\ \boxed{12},\ 15,\ ...\\\text{List of multiples of 4:}\ 0,\ 4,\ 8,\ \boxed{12},\ 16,\ ...\\\\12=3\cdot4\\\\\text{therefore}\\\\\dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12}\\\\\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\2\dfrac{2}{3}+12\dfrac{3}{4}=2\dfrac{8}{12}+12\dfrac{9}{12}=(2+12)+\dfrac{8+9}{12}=14+\dfrac{17}{12}\\\\=14+1\dfrac{5}{12}=15\dfrac{5}{12}

3 0
3 years ago
Please help me now plz
sergey [27]

Answer:

x=12

Step-by-step explanation:

The right side is a right triangle

The base is 1/2 of the bottom or 5

The height is x and the hypotenuse is 13

We can use the Pythagorean theorem

a^2 +b^2 = c^2

5^2 +x^2=13^2

25+x^2 = 169

Subtract 25 from each side

25-25+x^2 = 169-26

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Take the square root of each side

sqrt(x^2) = sqrt(144)

x= 12

4 0
3 years ago
Use your understanding of the unit circle and trigonometric functions to find the values requested.
vfiekz [6]

Answer:

a) For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

b) From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

6 0
2 years ago
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