by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
The answer is D.
Explanation:
I decided to start with 6 because it seemed to be the easiest. So you would out 6 in the place of ‘z’
6 ( 6 - 6 ) = 0
Here you would do the parentheses first
6 ( 0 ) = 0
6 * 0 = 0
0 = 0
You’re not done bc it could be both 6 and -6 So input where ‘z’ is and you should get
-6 ( -6 - 6 ) = 0
-6 ( -12 ) = 0
72 doesn’t equal 0
Hope this helped
Answer: c) 3.2 inches
<u>Step-by-step explanation:</u>
Let x represent the width of the frame
Then the area of the frame is:
(x + 12)(x + 14) = 261.44
Rewrite it in Standard form of a quadratic equation:
x² + 26x + 168 = 261.44
x² + 26x - 93.44 = 0
Use Quadratic Formula to solve for x:
Answer:
Answer Choice C
Step-by-step explanation:
Because it is dilated by a factor of 3
Answer:
261
Step-by-step explanation:
