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Andreyy89
3 years ago
13

Which functions have graphs that are steeper than the graph of f(x)=−3x^2?

Mathematics
1 answer:
netineya [11]3 years ago
8 0

Answer:

g(x)=−4x^2  and m(x)=4x^2

Step-by-step explanation:

A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number.  If this number is between 0 and 1, the graph will be stretched horizontally.  If this number is greater than 1, the graph will be shrunk horizontally.  If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.

The graphs that are horizontally shrunk are steeper than the others.  This is m(x)=4x^2  and g(x) = -4x^2.

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A rocket is launched from the ground and travels in a straight path. The angle of inclination of the rocket's path is 1.2 radian
gladu [14]

Answer:

a)S=2.57

b)H=203.2yard

c)X=121.79yards

Step-by-step explanation:

From the question we are told that:

Angle \theta=1.2=68.755^o

a)

Generally the equation for Slope is mathematically given by

 S=tan \theta

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b)

Given the right Angle triangle with horizontal distance x=85yard

Generally the equation for Height traveled is mathematically given by

 H=tan\theta*x

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 H=218.45

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c)

Generally the equation for Horizontal Distance traveled at 313 height traveled is mathematically given by

X=\frac{313}{tan65.75}

X=\frac{313}{2.57}

X=121.79yards

3 0
2 years ago
Which of the following measurements could be the side lengths of a right triangle?
notsponge [240]
The answer should be C but I’m not for sure ask your teacher sorry!!
6 0
3 years ago
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ivanzaharov [21]

Answer:

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Step-by-step explanation:

Information given

\bar X represent the sample mean

\mu population mean (variable of interest)

\sigma= 500 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The confidence2 level is 98% or 0.98 then the significance level would be \alpha=1-0.98=0.02 and \alpha/2=0.01, the critical value for this case would be z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94

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Mekhanik [1.2K]

Answer:

4

Step-by-step explanation:

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Answer:

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