The answer is (C)L= (P-2W)/2
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
Answer:
Step-by-step explanation:
![\sf 2x-1.5 = 2.1\\\\Add \ 1.5 \ to \ both \ sides\\\\2x = 2.1 + 1.5\\\\2x = 3.6\\\\Divide \ 2 \ to \ both \ sides\\\\x = 3.6 / 2\\\\x = 1.8\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%202x-1.5%20%3D%202.1%5C%5C%5C%5CAdd%20%5C%201.5%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%202.1%20%2B%201.5%5C%5C%5C%5C2x%20%3D%203.6%5C%5C%5C%5CDivide%20%5C%202%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cx%20%3D%203.6%20%2F%202%5C%5C%5C%5Cx%20%3D%201.8%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
5428.67 cubic inches88959.99 cm³<span>88.96 liters</span>
I think 115 min because its just 23 x 5 so you just multiply that to get the asnwer
