ABC is a right triangle at A such that

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

AB = 3(sq rt 48) - 5(sq rt 12) + sq rt3

AB = 3(sq rt 16x3) - 5(sq rt 4x3) + sq rt3

AB = 12(sq rt 3) - 10(sq rt 3) + sq rt3

AB = 3(sq rt 3)

AC = (3 - sq rt 6)(3 + sq rt 6)

AC = 9 + 3(sq rt 6) - 3(sq rt 6) -6

AC = 9 - 6

AC = 3

BC = (3 - sq rt 5)^2 + 2(3sq rt 5-4)

BC = 9 - 6sq rt 5m + 5 + 6sq rt 5 - 8

BC = 9 + 5 - 8 = 6

BC = 6

If right triangle, AB^2 + AC^2 = BC^2

(3sq rt 3)^2 + 3^2 = 6^2

27 + 9 = 36

36 = 36

You might be interested in

Giving brainlist to whoever answers

8_murik_8 [283]

Answer:

420

Step-by-step explanation:

volume = length x width x height

12 x 5 x 7 = 420

3 0

3 years ago

Read 2 more answers

What is the interquartile range of the data? 150, 165, 180, 198, 204, 216, 230, 255 A. 105 B. 51 C. 50.5 D. 28.5 ASAP!!! PLEASE

Reika [66]

<span>I Think the answer is a.

</span>

7 0

3 years ago

Given 6, 8, and 11 as the three sides of a triangle, classify it as one of the following acute, right or obtuse. Please help and

sp2606 [1]

9514 1404 393

Answer:

obtuse

Step-by-step explanation:

You may remember that side lengths of 3, 4, 5 make a right triangle. Doubling those lengths to 6, 8, 10 will still give a right triangle.

The given triangle has a longest side (11) longer than would be appropriate for a right triangle (10), so the largest angle is larger than 90°.

The triangle is obtuse.

Comparison of a triangle to a right triangle with two sides the same is one of several ways the triangle can be classified. You can use the Law of Cosines to find the largest angle, or you can use a triangle solver (as we have below).

In case you don't recall that 3-4-5 makes a right triangle, you can use the Pythagorean theorem to find the longest side of a right triangle with the given shorter sides:

hypotenuse = √(6² +8²) = √100 = 10

Your long side is longer, so your largest angle is larger than 90°.

Law of Cosines:

angle = arccos((6² +8² -11²)/(2·6·8)) = arccos(-21/96) ≈ 102.6°