Question

Simplify fully A) X^7 / X^3 B) Y^5 / Y^4

Answer 1

Hi,

$\frac{x^{a} }{x^{b} } =x^{a-b}$

a)

$\frac{x^{7} }{x^{3} }= x^{7-3} = x^{4}$

b)

$\frac{y^{5} }{y^{4} } = y^{5-4} = y^{1} = y$

;)