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Dimas [21]
2 years ago
8

One gallon of gasoline in Buffalo, New York costs $2.29. In Toronto, Canada, one liter of gasoline costs $0.91. There are 3.8 li

ters in one gallon.
Answer the questions below.

1. How much does one gallon of gas cost in Toronto? Round your answer to the nearest cent.



2. Is the cost of gas greater in Buffalo or in Toronto?



3. How much greater?
Mathematics
1 answer:
S_A_V [24]2 years ago
6 0

Answer:

The cost of one gallon of gas in Toronto, Canada is $3.458.

Solution:

Given, One gallon of gasoline in buffalo, New York costs $2.29.  

In Toronto, Canada, one liter of gas costs $0.91.  

There are 3.8 liters in one gallon.  

We have to find how much does one gallon of gas cost in Toronto?

Now, cost of one gallon of gas in Toronto = cost of one litre of gas in Toronto x 3.8 liters for 1 gallon.

Cost of one gallon of gas = 0.91 x 3.8 = 3.458

Hence, the cost of one gallon of gas in Toronto, Canada is $3.458.

dome7w and 28 more users found this answer helpful

Step-by-step explanation:

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-1/3,-0.3,1.2,4/3,3/2

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The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4
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Answer:

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

Mean = x1 = \frac{20+24+40+63+76+89}{6}

x1 = \frac{312}{6}

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Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37

The deviations will be added then.Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24

So the mean absolute deviation for city 1 is 24 ..

For city 2:

Mean = x2 = \frac{41+50+58+62+72+83}{6}

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Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22

The deviations will be added then.Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

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