Here is a scenario:
Mark recorded the following bowling scores for his last 9 games:
110, 92, 86, 203, 74, 105, 97, 112, 99
What was his mean score?
What was his median score?
Which of these better represents his bowling score for the last nine games?
Solution :
The null and alternative hypothesis is given by
Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05
Answer:
72 dollars I believe
Step-by-step explanation:
1 : 1.71 : 2.43
Step-by-step explanation:
What divided by 7= 1?
7/7 = 1
So use that answer for the other two dolls.
12/7 = 1.71
17/7 = 2.43
1 : 1.71 : 2.43
Have the same ratio as
7 : 12 : 17
