Answer:
would be in the second quadrant of the cartesian plane.
would be in the third quadrant of the cartesian plane.
Step-by-step explanation:
The horizontal and vertical axes of the cartesian plane divides the plane into four quadrants. By convention, these quadrants are numbered counterclockwise starting from the quadrant on the top right:
![\begin{array}{c|c}\text{Second Quadrant} & \text{First Quadrant} \\ \cline{1-2}\\[-1em] \text{Third Quadrant} & \text{Fourth Quadrant}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7D%5Ctext%7BSecond%20Quadrant%7D%20%26%20%5Ctext%7BFirst%20Quadrant%7D%20%5C%5C%20%5Ccline%7B1-2%7D%5C%5C%5B-1em%5D%20%5Ctext%7BThird%20Quadrant%7D%20%26%20%5Ctext%7BFourth%20Quadrant%7D%5Cend%7Barray%7D)
.
- Top-left: first quadrant.
- Top-right: second quadrant.
- Bottom-left: third quadrant.
- Bottom-right: fourth quadrant.
- Points on either axes (where at least one of the coordinates is
) are not in any of the four quadrants.
The 
-coordinate of the first point, , is 
, which is negative. Thus, this point would be to the left of the vertical axis.
Since the 
-coordinate of this point, 
, is positive, this point would be above the horizontal axis.
Thus, the point would be in the quadrant on the top-left corner of the cartesian plane. Therefore, this point would be in the second quadrant of the plane.
The second point would also be to the left of the vertical axis since the -coordinate of this point, 
, is negative.
This point would be below the horizontal axis since the -coordinate of this point 
is negative.
Thus, the point would be in the quadrant on the lower-left corner of the cartesian plane. This point would be thus be in the third quadrant of the plane.
