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katrin2010 [14]
3 years ago
7

In figure find the value of x triangle PQR 20 POINTSSSS

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

Divide

Step-by-step explanation:

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Proper angle for a ladder is about 75° from the ground. Suppose you have a 10 foot ladder. How far from the house should you pla
Alja [10]

Answer:

The base of the ladder is 2.58 m.

Step-by-step explanation:

Given that,

The angle of elevation for a ladder from the ground is 75°.

The length of a ladder, H = 10 foot

We need to find the distance from the house should you place the base of the latter. Let the base of the ladder is b. Using trigonometry,

\cos\theta=\dfrac{B}{H}\\\\B=H\times \cos\theta\\\\B=10\times \cos(75)\\\\B=2.58\ m

So, the base of the ladder is 2.58 m.

8 0
3 years ago
In the diagram below, AB || CD, EF || GH, and m m
Ne4ueva [31]

Answer:

Angle AJL=54

Step-by-step

3 0
3 years ago
A recipe needs 4/5 cups of butter for every 2 cups of flour. If you plan to use 3 cups of flour, how much butter will you need?
DedPeter [7]

Answer:

1 1/5 cups of butter

Step-by-step explanation:

4/5=2

      =3

 4/5 x 3=12/5

12/5 / 2

12/5 x 1/2=1 1/5

7 0
3 years ago
Read 2 more answers
The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form
azamat

Answer:

\large \boxed{y = (x - 5)^{2} + 2 }

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}The figure below shows that your parabola has its vertex at (5,2).

4 0
4 years ago
Writing equations of lines
Valentin [98]

Step-by-step explanation:

Equation of straight line is y=mx+c

choose any two points on straight line

for me I choose:(-3,11) and (3,-1)

use these two points to find gradient,m.

m= (-1-11)/(3-(-3))

m= -2

now, y=-2x+c

choose any point on the straight line

I choose point (3,-1)

sub the point into the equation to find c

-1=-2(3)+c

c=5

equation: y=-2x+5

7 0
3 years ago
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