We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
Answer:
y = 0.75x + 12
Step-by-step explanation:
The estimated total cost, y, of a child's toy is partially based on the number 1 point of batteries used, x. The cost of one battery is $0.75. The toy itself costs $12. Which equation represents the situation?
y = 12x + 0.75
y = 0.75x + 12
y = 12x − (775
y = 0.75x − 12
y = total cost of a child's toy
Cost of each battery = $0.75
Number of batteries = x
Cost of the toy = $12
Therefore,
total cost of a child's toy = Cost of the toy + Cost of each battery * Number of batteries
y = 12 + 0.75 * x
y = 12 + 0.75x
y = 0.75x + 12
Step-by-step explanation:
The correct answer for number 7 is B
Answer:299.94
Step-by-step explanation:youre welcome
