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3 years ago

14

A turtle travels mile in hour. At this rate, how far can the turtle travel in an hour

2 answers:

trapecia [35]3 years ago

7 0

Answer:

4 1/2

Step-by-step explanation:

The origional question is ¨A turtle travels 1/2 mile in 1/9 hour. At this rate, how far can the turtle travel in an hour¨ To be honest i have no clue how to explain it but that is the awanser.

jonny [76]3 years ago

4 0

Answer:

hey did you phrase the question wrong bc it says a turtle travels one mile in an hour then you are asking how far it travels in an hour

Step-by-step explanation:

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You push your younger sister on a swing one time and then allow your sister to

Ber [7]

Answer:

My sister will swing the total distance = 40 feet

Step-by-step explanation:

On the first swing my sister travels a distance of 8 feet.

In every successive swing she travels 80% of the distance of the previous distance.

So the sequence formed by the distance traveled in every swing will be a geometric sequence.

First term of the sequence 'a' = 8 feet

common ratio 'r' = 0.80

Since this sequence is an infinite geometric sequence,

Sum of this sequence = $\frac{a}{(1-r)}$ [Since r < 1]

= $\frac{8}{1-0.8}$

= $\frac{8}{0.2}$

= 40 feet

Therefore, my sister will cover the total distance = 40 feet

7 0

3 years ago

Simplify this expression

Gnesinka [82]

It’s A!! hope that helped

5 0

3 years ago

Read 2 more answers

The regular price of a camera is 180.00 the camera is on sale for 25% off the regular price. What is the sales price of the came

Marrrta [24]

Answer:

$135

Step-by-step explanation:

180 decrease 25% =

180 × (1 - 25%) = 180 × (1 - 0.25) = 135

8 0

3 years ago

4. Find the circumference of the circ All changes saved

Nat2105 [25]

Answer:

A. 62.8 in.

Step-by-step explanation:

Circumference of a circle = πd

Diameter (d) = 20 in.

Substitute

Circumference = π × 20

Circumference = 62.8318531

Circumference = 62.8 in. (Approximated to nearest tenth)

4 0

3 years ago

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

4 years ago