All categories

3 years ago

Gracie will go to the swimming pool on 20 different days this months.

Mathematics

1 answer:

Klio2033 [76]3 years ago

6 0

Answer:

Step-by-step explanation:

2.25 times 20 is 45 minus 30 is 15

You might be interested in

Which expression is equivalent to 4(7 + 8)? A) 11+8 B) 11+12 C) 28+12 D) 28+32

andreev551 [17]

To do this we take the outlier off the parenthesis (the 4) and multiply it by the two numbers inside the parenthesis...

4*7 + 4*8

28+32

7 0

3 years ago

Read 2 more answers

Find the distance between the two points.

Ksenya-84 [330]

Hey there!

Distance formula:

d = $\sqrt{(x_{2}-x_{1})+(y_{2}-y_{1}) }$

Plug in variables:

d = $\sqrt{(0-(-6))+(0-(-7))}$

Simplify.

d = $\sqrt{6+7}$

d = $\sqrt{13}$

The distance between the two points is $\sqrt{13}$ units.

Hope this helps!

4 0

4 years ago

I will give brainliest!! please help!!!

hram777 [196]

Answer:

Yes

Im pretty sure its like that dont hate if i get one wrong

6 0

4 years ago

Compare and contrast expanding and simplifying algebraic expressions with simplifying numeric expressions. For example, compare

larisa [96]

With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.

4 0

3 years ago

Read 2 more answers

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago