Chemosynthesis, I believe. Bacteria at the bottom of the ocean use this process for food.
Answer:
Theoretical yield of tungsten produced = 35.6836915592 ≈ 35. 68 g
Explanation:
The chemical equation can be expressed as follows;
WO3 (s) + 3H2(g) → W(s) + 3 H20(g)
Note that the equation is already balanced.
Molecular Mass of WO3= 183.84 + 15.999 × 3 = 183.84 + 47.997 = 231.837 g
From the equation 1 mole of WO3 reacts with 3 mole of hydrogen molecule.
Molecular mass of tungsten(W) = 183.84 g
1 mole of tungsten was produced from the chemical equation.
WO3 (s) + 3H2(g) → W(s) + 3 H20(g)
From the equation,
231. 837 g of WO3 produces 183.84 g of tungsten
45.0 g of WO3 will produce ?
grams of tungsten produced = 183.84 × 45 /231.837
grams of tungsten produced = 8272.8
/231.837
Theoretical yield of tungsten produced = 35.6836915592 ≈ 35. 68 g
Answer:
4
Explanation:
If both parents were Hetero brown, they would both have this allele: Bb.
If you were to draw a punnet square, the outcomes would be: BB, Bb, Bb, and bb.
There would be a 75% chance of the offspring having brown eyes and a 25% chance of the offspring having blue eyes.
The fluid inside of the Extracellular Matrix is Extracellular Fluid. Extracellular Fluid is also called ECF. ECF is mostly tissue fluid. It is also made up of a large amount of intravascular fluid. The remaining smaller amount of ECF is transcellular fluid.
hope i could help :)
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
