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Reil [10]
3 years ago
5

Matea recorded that water levels in one part of the river fell 1.05 millimeters per year for 2.48 years. Describe how you could

estimate the total variation in water level.
Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0

Answer:

the answer is -13.64 i just took the test and it right promise.

Step-by-step explanation:

mark me as brainliest pls its right

horsena [70]3 years ago
6 0

Answer:

The decrease of the decimal rate -1.05 mm/year can be rounded to -1. You don’t need to round 2.48 because you’re multiplying by -1. Since -1.05 is negative and rounded to a greater value, the estimate could be adjusted to a slightly lesser value, maybe -2.5 or -2.6

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baherus [9]

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8 0
3 years ago
A.) A new cell phone costs $625. Its sale price is $500. What’s the percent of decrease?
Andrej [43]

Answer:

175$

Step-by-step explanation:

8 0
2 years ago
If a=-6 and b=-10 evaluate the following:<br>a + 6​
ser-zykov [4K]

Answer:

-6+-10=-16

Step-by-step explanation:

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6 0
3 years ago
A book store has twice as many history books as science books. The store has 81 history and science books altogether how many of
atroni [7]

let h= history books

science books = s

h=2s  there are 2 times as many history as science so to get them equal we double the science

h+s=81    there are 81 total history and science books

2s+s=81   substitute 2s for h in the above equation

3s = 81   combine like terms

s = 27

There are 27 science books

h=2s

h=2(27)

h=54

there are 54 history books

4 0
3 years ago
The area of sector A08 is 48x and m&lt;AOB = 270º. Find the radius of circle O.
Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ is the measure of the central angle of the circle. For us, that fills in as follows:

48\pi=\frac{270}{360}*\pi r^2 and manipulate it as follows:

r^2=\frac{(360)(48\pi)}{270\pi} the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ again is the measure of the central angle of the circle, 90°:

A_s=\frac{90}{360}(3.1415)(10)^2 which simplifies a bit to

A_s=\frac{1}{4}(3.1415)(100), giving us an area of

A_s=78.5375m^2. Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

A_t=\frac{1}{2}(10)(10) which is

A_t=50m^2

Subtract that from the area of the sector to get that the shaded area is 28.5 square meters, choice A.

4 0
3 years ago
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