Write the equation for the line tangent to the circle x2 + y2 = 29 at the point (2, 5).
1 answer:
X2 + y2 = 29 Center of the circle x=0 and y=0 Therefore the slope of the line perpendicular to the tangent line (y2-y1) / (x2-x1) (5-0) / (2-0) 5/2 so the slope of the tangent -2/5 General equation for the line y = mx + c if the line satisfies with the point (2,5) 5 = 2m + c m = -2/5 5 = 2 * (-2/5) + c c = 5 + (4/5) c = 29/5 Therefore the equation of the line y = mx + c y = (-2/5) m + 29/5
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