Write the equation for the line tangent to the circle x2 + y2 = 29 at the point (2, 5).

1 answer:

3 0

X2 + y2 = 29

Center of the circle
x=0 and y=0

Therefore the slope of the line perpendicular to the tangent line
(y2-y1) / (x2-x1)
(5-0) / (2-0)
5/2

so the slope of the tangent
-2/5

General equation for the line
y = mx + c
if the line satisfies with the point (2,5)
5 = 2m + c

m = -2/5

5 = 2 * (-2/5) + c
c = 5 + (4/5)
c = 29/5

Therefore the equation of the line
y = mx + c
y = (-2/5) m + 29/5

You might be interested in

Please help!

postnew [5]

Lets solve the equation first:
 0.5 – |x – 12| = –0.25
= 1/2 - |x - 12| = -1/4
= 2 - 4|x - 12| = -1
= 4|x - 12| = 3
= |x - 12| = 0.75
positive case, x >= 12
x - 12 = 0.75
x = 12.75
negative case, x < 12
x - 12 = -0.75
x = 11.25
So those are the two solutions.
These apply:
1.) The equation will have no solutions.
2.) A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
3.) A good first step for solving the equation is to split it into a positive case and a negative case.
5.) The negative case of this equation is x – 12 = –0.75.

7 0

4 years ago

Read 2 more answers

3) Scenario 1 Scenario 2 y = 50x x is time in hours y is distance in miles Compare the scenarios and determine which shows the g

Olegator [25]

Answer:

Option A.

Step-by-step explanation:

Consider the below figure attached with this question.

Scenario 1 represented by the graph.

From the graph it is clear that the line passes through the points (1,60) and (2,120).

Slope of the line is