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Elan Coil [88]
3 years ago
8

What motivated Barbara MBANEFO to become an engineer?

Computers and Technology
2 answers:
luda_lava [24]3 years ago
8 0

Answer:

to help her community and give hope to others

Explanation:

olga55 [171]3 years ago
6 0
She was very helpful, kind and cooperative to others and other people also inspire her to be an engineer.
You might be interested in
1k bits equals to how many bits
ruslelena [56]

Answer:

1000 bits

Explanation:

hope it helps :D

8 0
3 years ago
Write a recursive method that finds the number of occurrences of a specified letter in a string using the following method heade
Dafna1 [17]

Answer:

//Java program to find the number of occurrences of a specified character in a string.

// Import the required packages.

import java.io.*;

import java.util.*;

//class declaration

class CharacterCount

{

// Main method.

public static void main (string args[ ] )

{

  try

      {

     // Taking the input from the user.

         System. out.print ("Type a string to analyze: ");

     // Creating the scanner class object.

         scanner input = new scanner (system. in);

         String str = input .next();

         System.out.print("Type a character to check: ")

         String temp = input.next();

         char c = temp.charAt(0);

     // Calling the method to get the character count.

         int count = <em>count</em>(str,c);

     // Displaying the result.

         system.out.print In("There are " + count + " " + c + " 's. ");

     // catching the exception.

         catch(Exception e)

         System.out.print In("Exception has occured in the class . Program will exit. ");

      // Exiting the system.

         System.exit(0);

         }

}

// Method to calculate the character count.

public static int count(String str, char a)

  {

    // checking for null string input.

      if(str.equals(""))

      {

       return 0;

      }

      else

      {

      int k = 0;

    // Character matching check.

      if ( str.substring(0, 1) . equals (Character.<em>toString</em>(a)) )

      {

   // Incrementing the counter.

      k++;

      }

   // Recursive call

      k += <em>count</em>(str.substring(1) , a);

              return k;

       }

     }

}

Explanation:

Output should show: Type a string to analyze: welcome

                                   Type a character to check: e

                                   There are 2 e's.

3 0
4 years ago
Given six memory partitions of 300 KB, 600 KB, 350 KB, 200 KB, 750 KB, and 125 KB (in order), how would the first-fit, best-fit,
Inga [223]

Answer:

In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.

Explanation:

We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).

Using First-fit

First-fit means you assign the first available memory that can fit a process to it.

  • 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
  • 500KB will fit into the second partition. So, F2 will have a remaining free space of  100KB (600 - 500)
  • 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
  • 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
  • 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)

Using Best-fit

Best-fit means you assign the best memory available that can fit a process to the process.

  • 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
  • 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
  • 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
  • 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
  • 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)

Using Worst-fit

Worst-fit means that you assign the largest available memory space to a process.

  • 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
  • 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
  • 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
  • 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
  • 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
8 0
3 years ago
Why should you open your door with your right hand when parked on a right-side curb?
meriva

Answer:

B. So that you will be forced to look behind the car for an approaching bicyclist.

Explanation:

The main reason for opening with your right hand in this scenario is so you can look behind you for a bicyclist, etc. It's a good practice as you never know if someone is behind you or of the likes. Many people usually open the door with their left hand. The problem with this is that they're not forced to look behind them and can be oblivious to people, bicyclists, etc. behind them.

<u>Hope this helps and have a nice day!</u>

5 0
4 years ago
Suppose a linked list of 20 nodes. The middle node has a data –250. Write the pseudocode to replace the middle node of the linke
dexar [7]

Answer:

The middle node has a data –250. ... Write The Pseudocode To Replace The Middle Node Of The Linked List With ... Assume That The List's Head Pointer Is Called Head_ptr And The Data For The New Node Is Called Entry ... Assume that the list's head pointer is called head_ptr and the data for the new node is called entry ...

Explanation:

4 0
4 years ago
Read 2 more answers
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