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3 years ago

A light bulb consumes 5400 watt-hours in 3 days and 18 hours. How many watt-hours does it consume per day?

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

We are given:

Time period: 3 days and 18 hours

Energy consumed in given time period: 5400 watt-hours

Converting time to hours:

We know that one day is 24 hours

So, 3 days = 72 hours

Time period = 3 days + 18 hours

Time period = 72 hours + 18 hours

Time period = 90 hours

Converting to days

Time period = 3.75 days

Watt-hour consumption in a day:

Consumption = 5400 watt-hours / 3.75 days

Consumption = 1440 watt-hours/day

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Answer:

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Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, find the margin of error M as such

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How large a sample must she select if she desires to be 90% confident that her estimate is within 4 ounces of the true mean?

A sample of n is needed, and n is found when M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 1.96\frac{\sigma}{\sqrt{n}}$

$4\sqrt{n} = 1.96\sqrt{\sigma}$

$\sqrt{n} = \frac{1.96\sqrt{\sigma}}{4}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{\sigma}}{4})^2$

$n = (\frac{1.96\sqrt{\sigma}}{4})^2$

The minimum sample size needed is $n = (\frac{1.96\sqrt{\sigma}}{4})^2$ . If n is a decimal number, it is rounded up to the next integer. $\sigma$ is the standard deviation of the population.

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Step-by-step explanation:

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