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Yakvenalex [24]
3 years ago
9

Jennifer has a string attached to the end of a buoy with extra string coiled on the bottom of the tank. She measures the length

of the string from where it is attached to the buoy to the bottom of the tank as he adds more water to the tank. The length changes linearly as water is added. The table shows the collected data. What is the slope of the line that models the data?
Mathematics
2 answers:
Elena L [17]3 years ago
7 0
Its A,,,,,,,,,,,,,,,,,,,,,,, <span>Jennifer has a string attached to the end of a buoy with extra string coiled on the bottom of the tank. She measures the length of the string from where it is attached to the buoy to the bottom of the tank as he adds more water to the tank. The length changes linearly as water is added. The table shows the collected data. What is the slope of the line that models the data?

</span>
Sindrei [870]3 years ago
6 0

Answer: The correct answer would be 1.5. I have taken the test.

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What is the common ratio of the sequence?<br> -2,6,-18,54
aivan3 [116]

<u>ANSWER</u>

The common ratio is -3.

<u>EXPLANATION</u>

In general, the common ratio of a Geometric Sequence is given by:

r = \frac{a_{n+1}}{a_{n}}

We can find the common ratio using any two consecutive terms of the geometric sequence by dividing the subsequent term by the previous term.

The given sequence is -2,6,-18,54

Using the first two terms the common ratio is

r =  \frac{6}{ - 2}  =  - 3

We could also used the second and third terms to get

r =  \frac{ - 18}{6}  =  - 3

and so on and so forth.

Therefore the common ratio is -3.

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3 years ago
Find the length of arc JK. <br> (Round to the nearest hundredth).
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A rectangular swimming pool measures 50 meters in length and 25 meters in width. A scale drawing of the swimming pool will be ma
igomit [66]

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3 years ago
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Help!!! please what's is the figure​
S_A_V [24]

Hello from MrBillDoesMath!

Answer:

108 cm^2

Discussion:

The area of the logo  =

area of Trapezoid on top (I)  + area of triangle on bottom (II)

I  = (1/2) h ( b1 + b2)            h = altitude, b1, b2 = bases

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II  = (1/2) b h

   = (1/2) (12) ( 15 - 6)               => altitude of triangle = 15 - 6 NOT (1/2) 15

   =  54

I + II= 54 + 54 = 108

Thank you,

MrB

3 0
3 years ago
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8 = 4 - 2x<br> - 2x +5 = 17<br> 12= - 3 ( x+ 5)
max2010maxim [7]
8 = 4 - 2x\\8 + 2x = 4\\2x = -4\\x = -2

- 2x +5 = 17\\-2x =12\\x = -6

12= - 3 ( x+ 5)\\12 = -3x -15\\-3x =27\\x= -9
5 0
3 years ago
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