So if a cubic box has a side length of 2 ft in order to find the volume we need to cube it or multiply the length times 3 times. so it would be 2x2x2=8. that is the volume of the fiest cube. in order to find the volume of the larger cube first you need to know the length of one of the sides. the base has 4 sides to it that are all equal so you divide 24 by 4 and get 6. then to find the volume you multiply 6 three times since it is also a cubic cube so it would be 6x6x6=216. now you know the volume of each cube so you divide 216 by 8 to find how many times the volume of the small cube would go into the volume of the larger cube and get 27 times.

6 0

3 years ago

Nathan bought a cd for his friend. The length and width of the cd case is 4 18⁄25 inches. What is the area of the cd case?

ale4655 [162]

Answer:

Hence the area of CD bought by Nathan is <em>22.2784 square inches.</em>

Step-by-step explanation:

The length and width of a CD bought by Nathan is $4\frac{18}{25}=\dfrac{118}{25}$ inches.

As CD have the same length and width this means it will be of the shape of a square.

Hence, the area of CD is given by:

Area of CD=length×width

= $4\dfrac{18}{25}\times4\dfrac{18}{25}$

= $\dfrac{118}{25}\times\dfrac{118}{25}$

= $\dfrac{118\times118}{25\times25}$

= $\dfrac{13924}{625}$

= $22.2784$

Hence the area of CD bought by Nathan is 22.2784 square inches.

3 0

3 years ago

Logx(8x-3)-logx 4=2<br> please help ill give you everything i have !!

Gelneren [198K]

Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2

2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2

Answer: Two solutions: x=1/2 and x=3/2

6 0

3 years ago