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katovenus [111]
3 years ago
5

Parallel to y=1/3x and through (6,2)

Mathematics
1 answer:
ddd [48]3 years ago
5 0

Answer: The line already goes thru 6,2 because 6=1/3(2) So the equation is y=1/3x


Step-by-step explanation:

(y-2)=1/3(x-6)

y-2=1/3x-6/3

y=1/3x

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Stella divides 12/8 on her calculator and gets 1.5. Assuming that Stella has not adjusted the calculator's settings, what do the
Romashka [77]

Stella divided 12/8.

If we divide 12 by 8, we get exactly 1.5.

Let us check given options one by one .

A) Stella made an error : Stella didn't made an error because it's just division of two numbers.

B) The answer is exactly 1.5.  : On dividing 12 by 8, we get exactly 1.5, so this option is correct.

C) The calculator rounded the answer. : On dividing 12 by 8, we get exactly 1.5. So, no rounding is required.

D) The calculator truncated the answer. : On dividing 12 by 8, we get exactly 1.5. So, no truncation in the answer.

Therefore, correct option is B) The answer is exactly 1.5.

6 0
3 years ago
Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0
3 years ago
There are 6 sixth graders , 7 seventh graders , and 8 eight graders entered in a contest.
fgiga [73]

Answer:

See below ~

Step-by-step explanation:

<u>P (6th grader)</u>

  • No. of 6th graders / Total students
  • 6 / 6 + 7 + 8
  • 6/21
  • 2/7

<u>P (6th grader after)</u>

  • No. of 6th graders - 1 / Total students - 1
  • 6 - 1 / 21 - 1
  • 5/20
  • 1/4

<u>Question 1 : P (Both 6th graders)</u>

  • P = P (6th grader) × P (6th grader after)
  • P = 2/7 x 1/4 = 2/28 = <u>1/14</u>

<u></u>

<u>Question 2 : P' (Both 6th graders)</u>

  • P' = 1 - P
  • P' = 1 - 1/14
  • P' = <u>13/14</u>
4 0
1 year ago
Read 2 more answers
How yo day going :)))))))))))))))))))))))))))
mrs_skeptik [129]

Answer:

Pretty good, how are you?

8 0
2 years ago
Read 2 more answers
Solve for x 5x - 5 = 5
Viktor [21]

Polynomial equation solver

5x - 5 = 5

Standard form:

5x − 10 = 0

Factorization:

5(x − 2) = 0

Solutions:

x = 10

5

= 2

7 0
3 years ago
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