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Lisa [10]
3 years ago
8

Part 1

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0
Because December is really cold
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Find the area of the figure by subtraction.
arsen [322]

Answer:

<em>56</em>

Step-by-step explanation:

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3 years ago
Solve for x in the equation x²-12x+59=0
lyudmila [28]

{x}^{2}  - 12x + 59 = 0 \\  {x}^{2}  - 12x + 36 + 23 = 0 \\  {x}^{2}  - 12x + 36 =  - 23 \\  {(x - 6)}^{2}  =  - 23 \\ x - 6 =  +  -  \sqrt{ - 23}  =  +  - i \sqrt{23}  \\ x = 6 +  - i \sqrt{23}

mean

x = 6 + i \sqrt{23}

or

x = 6 - i \sqrt{23}

7 0
3 years ago
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How do I solve this? can someone please help? thank you! y=3x+4 y=x-2 ​
Alecsey [184]

Answer:

Step-by-step explanation:

y = 3x+4 and y = x-2

3x+4 = x-2

2x+4 = -2

2x = -6

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8 0
3 years ago
Radius= 4cm. find the area and diameter of the circle​
Bezzdna [24]
<h3>given:</h3>

radius= 4 cm

<h3>to find:</h3>

the area and the diameter of the circle.

<h3>solution:</h3><h3>diameter:</h3>

d = 2r

d = 2 \times 4

d = 8 \: cm

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>diameter</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>8</u><u> </u><u>centimeters</u><u>.</u>

<h3>area:</h3>

a = \pi {r}^{2}

a = \pi \times  {4}^{2}

a = 50.26548 \:  {cm}^{2}

a = 50.27 \:  {cm}^{2}

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>50.27</u><u> </u><u>square</u><u> </u><u>centimeters</u><u>.</u>

6 0
3 years ago
Read 2 more answers
WCLN PCMath1l - Rev. Sept/2018
Verdich [7]

Answer:

\frac{p + 1}{p - 8}

Step-by-step explanation:

The  \: slope: \frac{2p + 1 - p}{p - 5 - 3}  =  \frac{p + 1}{p - 8}

4 0
3 years ago
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