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miskamm [114]
3 years ago
11

If I was 2 years old, and my sister was half my age. How old would my sister be?

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0
My sister would be one years old. 
2÷2=1
schepotkina [342]3 years ago
3 0
Well by dividing you will get your answer. 
What is 2 ÷ 1?

Your sister would be 1 year old.
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We tried so many ways but we are just that stupid. Please explain work.
Roman55 [17]
25 Yards, three ribbons, so 25*3, thats 75 yards.
Convert 75 yards to Inches, you get 2700 inches, divide 2700 by 22.
You get 122.72 Repeating, round up.
Your Answer is A, 123


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3 0
3 years ago
Read 2 more answers
Complete the equation. (x-2)(x^2 + 2x + 4) = ( , )
yanalaym [24]

Answer:

Step-by-step explanation:

x(x² + 2x + 4)-2((x² + 2x + 4)

x³+2x²+4x -2x²-4x-8

x³-8

6 0
2 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
3 years ago
For each formula,rearrange so a is by itself:
vichka [17]

Step-by-step explanation:

a) 6-9b=3a

First:Subtract

3b=3a

Second: Devide

3b/3a

=(3÷3)(b÷a)

=1b/a

= b/a

B) 6b+2a=3a

First:Transpose (Group the like terms. signs will change.)

-3a+2a=-6b

=-1a=-6b

Second:Divide

=-1a/-6b:(-1÷-6)(a÷b)

=1a/6b

=a/6b

C)a/3=b+2

First: Transpose

a=3+2+b

=a/6+b

6 0
3 years ago
Which of the following is a result of shifting a circle with equation (x + 3)² + (y - 2)² = 36 left 3 units?
Furkat [3]
A circle with equation:
( x + 3 )² + ( y - 2 )² = 36
Center of a circle: C ( - 3, 2 )
r = 6 ( the radius of a circle stays the same )
After shifting 3 units left : C 1 ( - 6, 2 ).
Answer:
( x + 6 )² + ( y - 2 )² = 36 
5 0
3 years ago
Read 2 more answers
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