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sergiy2304 [10]
3 years ago
5

Please help me on my precalculus test.

Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

14. Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

If <em>x</em> is in quadrant 1, then both sin(<em>x</em>) and cos(<em>x</em>) are positive, so

sin²(<em>x</em>) + cos²(<em>x</em>) = 1   →   cos(<em>x</em>) = + √(1 - sin²(<em>x</em>))

which gives cos(<em>x</em>) = 4/5. Then

sin(2<em>x</em>) = 2 • (3/5) • (4/5) = 24/25

15. Recall the double angle identity for cosine:

cos(2<em>x</em>) = cos²(<em>x</em>) - sin²(<em>x</em>)

which we can rewrite in terms of sin(<em>x</em>) only as

cos(2<em>x</em>) = 1 - 2 sin²(<em>x</em>)

Then cos(2<em>x</em>) = 1 - 2 • (3/5)² = 7/25

16. Recall the definition of tangent:

tan(<em>x</em>) = sin(<em>x</em>) / cos(<em>x</em>)

Then tan(2<em>x</em>) = sin(2<em>x</em>) / cos(2<em>x</em>) = (24/25) / (7/25) = 24/7

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