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3 years ago

1. Define y-intercept of a line?

Mathematics

1 answer:

BartSMP [9]3 years ago

4 0

1. The y-intercept of a line is on a graph where a line crosses through the y axis.

2. b is the y- intercept and m is the slope. For example something using y=mx+b could be written like y=3x+2 if the y-intercept is 2 and the slope is 3.

3. The slope is what describes the direction and steepness of a line on a graph. Rise and run mean that when you find a slope you must first find the rise over run. You must go from one dot on a graph to the next by first going up or down to where that you are on the same number on the y axis that the next point is, next go on the x axis and go left or right until you have reached the next point. For example if you went up 3 and over 2, the rise would be 3 and the run would be 2. The slope in that situation would be 3/2.

Hope this helps you.

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Find the matrix A of the linear transformation T(f(t))= 4f'(t)+6f(t) from P2 T0 P2 with respect to the standard basis of P2 {1,t

dimulka [17.4K]

Answer: The required matrix is

$A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .$

Step-by-step explanation: The given linear transformation is

T(f(t)) = 4f'(t) + 6f(t).

We are to find the matrix A of T from P² to P² with respect to the standard basis P² = {1, t, t²}.

We have

$T(1)=4\times\dfrac{d}{dt}1+6\times1=0+6=6\times 1+0\times t+0\times t^2,\\\\T(t)=4\times\dfrac{d}{dt}t+6\times t=4+6t=4\times1+6\times t+0\times t^2,\\\\T(t^2)=4\times\dfrac{d}{dt}t^2+6\timest^2=8t+6t^2=0\times 1+8\times t+6\times t^2.$

Therefore, the matrix A is given by

$A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .$

Thus, the required matrix is

$A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .$

6 0

3 years ago

Mrs. Hilt has 6 pizzas. Each pizza has 6 slices. She

Ede4ka [16]

Answer:

Step-by-step explanation:

6 pizzas with six slices: 6*6=36---> she has 36 slices

1/4 of 36= how many she sold

1/4(36) or 36/4= 9

she sold 9 slices

36-9= the amount she has left

which is 27

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3 years ago

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Laker Company reported the following January purchases and sales data for its only product. Date Activities Units Acquired at Co

Serjik [45]

Complete Question,

Q) Laker Company reported the following January purchases and sales data for its only product. Date Activities Units Acquired at Cost Units sold at Retail Jan. 1 Beginning inventory 140 units @ $ 6.00 = $ 840 Jan. 10 Sales 100 units @ $ 15 Jan. 20 Purchase 60 units @ $ 5.00 = 300 Jan. 25 Sales 80 units @ $ 15 Jan. 30 Purchase 180 units @ $ 4.50 = 810 Totals 380 units $ 1,950 180 units Required: The Company uses a periodic inventory system. For specific identification, ending inventory consists of 200 units, where 180 are from the January 30 purchase, 5 are from the January 20 purchase, and 15 are from beginning inventory. Determine the cost assigned to ending inventory and to cost of goods sold using

(a) specific identification

(b) weighted average

(c) FIFO

(d) LIFO

Answer:

Specific Identification Method:-

Ending Inventory = $925.

Costs of goods Sold = $1025.

Weighted Average Method:-

Ending Inventory = $1026.

Costs of goods Sold = $924

FIFO Method:-

Ending Inventory = $910.

Costs of goods Sold = $1040

LIFO Method:-

Ending Inventory = $1140.

Costs of goods Sold = $=810

<h3>Step-by-step explanation:</h3>

(a) Specific identification method:

Ending inventory:

180 units * $4.50 = $810

5 units * $5 = $25

15 units * $6 = $90

200 units * 0 = 0

$810 + $25 + $90 + 0= $925

Cost of goods sold:

125 units * $6 = $750

55 units * $5 = $275

180 units * 0 = 0

$750 + $275 + 0 = $1025

(b) Weighted average method:

Weighted average rate/unit = $1950 / 380 units = $5.131579

Cost of goods sold:

180 units * $5.131579 = $924

Ending inventory:

200 units * $5.131579 = $1026.

(c) FIFO

Cost of goods sold:

140 units * $6 = $840

40 units * $5 = $200

180 units * 0 = 0

$840 + $200 + 0 = $1040

Ending inventory:

20 units * $5 = $100

180 units * $4.50 = $810

200 units * 0 = 0

$100 + $810 + 0 = $910

(d) LIFO

Cost of goods sold:

180 units * $4.5 = $810

180 units * $0 = 0

$810

Ending inventory:

140 units * $6 = $840

60 units * $5 = $300

200 units * $0 = $0

$840 + $300 = $1140

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3 years ago

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lbvjy [14]

Answer:

M -24 because math is a thing and I have to have a minimum of twenty characters

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3 years ago

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The dimensions of a big dog house are 2 1/2 the dimensions of a small dog house. If the width of the small doghouse is 2 feet, w

Alchen [17]

The width of the big dog house is 2.5 times the small dog house.
multiply 2 by 2.5 to get your answer. hope this helps :)

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4 years ago