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gavmur [86]
3 years ago
13

WILLL GIVE BRAINLEST WILL GUVE BRAINLEST Photo is attached!! Thanks I appreciate if u help

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

1 false

2 true

3 true

4 false

5 true

Step-by-step explanation:

f(a) = (2a - 7 + a^2) and g(a) = (5 – a).

1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial

When added together, they will be a second degree polynomial

2. true  When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction

3.  true  f(a) + g(a) = (2a - 7 + a^2) + (5 – a)

Combining like terms = a^2 +a -2

4.  false   f(a) - g(a) = (2a - 7 + a^2) - (5 – a)

Distributing the minus sign (2a - 7 + a^2) - 5 + a

Combining like terms  a^2 +3a -12

5.  true  f(a)* g(a)  = (2a - 7 + a^2)  (5 – a).

Distribute

                      (2a - 7 + a^2)  (5)  – (2a - 7 + a^2)  (a)

                       10a -35a +5a^2 -2a^2 -7a +a^3

Combining like term

-a^3 + 3 a^2 + 17 a - 35

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A concrete beam may fail either by shear (S) or flexure (F). Suppose that three failed beams are randomly selected and the type
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Answer:

\begin{array}{cc}{Outcome} & {X's} & {FFF} & {0} & {SFF} & {1}  & {FSF} & {1} & {FFS} & {1} & {FSS} & {2}& {SFS} & {2}& {SSF} & {2}& {SSS} & {3} \ \end{array}

Step-by-step explanation:

Given

S_S = \{FFF, SFF, FSF, FFS, FSS, SFS, SSF, SSS\}

X \to Number of beams failed by shear

Required

List each outcome and the value of X

To do this, we simply count the occurrence of S in each outcome.

This is tabulated as follows:

\begin{array}{cc}{Outcome} & {X's} & {FFF} & {0} & {SFF} & {1}  & {FSF} & {1} & {FFS} & {1} & {FSS} & {2}& {SFS} & {2}& {SSF} & {2}& {SSS} & {3} \ \end{array}

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2. Use the distributive property to write an expression that is equivalent to 12 + 4x.
fredd [130]

Answer:

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Step-by-step explanation:

So with the distrubutive property, you look at the numbers you have, and then take the greatest common factor between the two.

So lets think about it, what goes into both 12 and 4?

2 does, but is that the greatest common factor? No.

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So, what do we get when we take 4 from 4x? We get 1x, or just x.

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Now, lets take the common greatest factor, and our two new numbers and put them back into the expression.

Remember that the greatest common factor, the one you took from the other numbers, is what goes first:

4()

Remember to put the parethese there, or else you would only be multiplying the first number by 4, and not the second.

Next lets put the other numbers in. In most expressions, you should put the x number in first, and the normal number in second. So it should now be:

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Hope this helps! ;)

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