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Varvara68 [4.7K]

3 years ago

14

Please help me I’m super stuck!!

1 answer:

Ulleksa [173]3 years ago

8 0

The answer is 25 it takes alto of steps thou so u can use this as a answer to check our work

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The average time a boulder high varsity lacrosse player plays in a game is 30 minutes with a standard deviation of 7 minutes. no

Alekssandra [29.7K]

Solving this problem is pretty straight forward.

We simply use the formula:

z-score = (x – u) / s

where,

x = sample value = 48 minutes

u = mean value = 30 minutes

s = standard deviation = 7 minutes

Therefore,

z-score = (48 minutes – 30 minutes) / 7 minutes

<span>z-score = 2.57</span>

7 0

2 years ago

A plan to expand megans room will make the length 140% what will be the new length of the room?

LekaFEV [45]

Answer:

you need to know the original length to figure this one out

Step-by-step explanation:

when you get the original length, you multiply by 1.4 to figure this one out.

7 0

2 years ago

Find the difference between 900 and 246

Svetlanka [38]

The answer is 900-246=654

4 0

2 years ago

PLEASE HELP ASAP

Crank

Option D: $f(x)=-2(x+2)(x-4)$ is the function

Explanation:

Let the general form of quadratic equation be $y=a x^{2}+b x+c$

The function passes through the intercepts $(-2,0)$ and $(4,0)$ and also passes though the point $(-1,10)$

Substituting the points $(-2,0)$ , $(4,0)$ and $(-1,10)$ in the equation $y=a x^{2}+b x+c$ , we get,

$4a -2b+c=0$ -----------(1)

$16a +4b+c=0$ ----------(2)

$a-b+c=10$ -----------(3)

Subtracting (1) and (2), we get,

$\ \ 4a -2b+c=0\\ 16a +4b+c=0\\\---------\\ \ \ -12a-6b=0$ -----------(4)

Subtracting (2) and (3), we get,

$16a +4b+c=0\\\ \ a \ \ - \ \ b \ +c=10\\---------\\15a+5b=-10$ ------------(5)

Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,

$-60a-30b=0\\\ 90a+30b=-60\\--------\\30a=-60\\\ \ a=-2$

Thus, the value of a is $a=-2$

Substituting $a=-2$ in equation (4), we get,

$\begin{aligned}-12 a+6 b &=0 \\-12(-2)-6 b &=0 \\ 24-6 b &=0 \\ 24 &=6 b \\ 4 &=b \end{aligned}$

Thus, the value of b is $b=4$

Now, substituting the value of a and b in equation (1), we have,

$\begin{aligned} 4 a-2 b+c &=0 \\ 4(-2)-2(4)+c &=0 \\-8-8+c &=0 \\ c &=16 \end{aligned}$

Thus, the value of c is $c=16$

Now, substituting the value of a,b and c in the general formula $y=a x^{2}+b x+c$ , we get,

$y=-2x^{2} +4x+16$

Taking out the common term as -2 we get,

$y=-2(x^{2} -2x-8)$

Factoring , we get,

$y=-2(x+2)(x-4)$

Thus, the function is $f(x)=-2(x+2)(x-4)$

7 0

2 years ago

Expand logarithms equation

Bess [88]

Answer:

$log_2(x) + log_2(y) + log_2(z)$

Step-by-step explanation:

$5log_2(xyz)^{1/5}\\\\5log_2(x)^{1/5} + 5log_2(y)^{1/5} + 5log_2(z)^{1/5}\\\\log_2(x) + log_2(y) + log_2(z)$

4 0

3 years ago