Answer:
ayo
Step-by-step explanation:
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Answer:
D
Step-by-step explanation:
f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15) Remove the brackets
f(x) - g(x) = -9x^2 - 7x + 12 - 3x^2 + 4x + 15
f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15
f(x) - g(x) = -12x^2- 3x + 27
Answer D
Answer:
- x = arcsin(√20.5 -3√2) +2kπ . . . k any integer
- x = π - arcsin(√20.5 -3√2) +2kπ . . . k any integer
Step-by-step explanation:
Add √(82) -3sin(x) to both sides to get ...
2sin(x) = √82 -√72
Now, divide by 2 and find the arcsine:
sin(x) = (√82 -√72)/2
x = arcsin((√82 -√72)/2)
Of course, the supplement of this angle is also a solution, along with all the aliases of these angles.
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In degrees, the solutions are approximately 16.562° and 163.438° and integer multiples of 360° added to these.
Answer:
I don't know if you have heard of this question but if you
D. -4
sq rt of 3x+28-8=x
add 8 to both sides
sq rt of 3x+28 = x+8
square both sides of the equation
3x + 28 = x^2 + 16x + 64
subtract x^2+16x+64 from both sides
group common terms
-13x-36-x^2=0
rearrange and put in quadratic form
x= -13 +/- sq rt of 13^2-4(1)(36) over 2(1)
subtract 169 by 144
x= -12 +/- sq rt of 25 over 2
solve for both sides
x = -13+5 over 2
=-4
x= -13-5 over 2
= -9
now plug in x
sq rt of 3(-4)+28 -8=-4
sq rt of 3(-9)+28 -8= -9
-4 = -4
but
-7 does not = -9
so -4 is the solution
