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3 years ago

What is the degree of the polynomial function f(x) = 2x3 + 7x5 − 4x − 12?

Mathematics

2 answers:

djverab [1.8K]3 years ago

5 0

Answer:

degree of the polynomial is 5.

Step-by-step explanation:

We have been given the polynomial $f(x)=2x^3+7x^5-4x-12$

We can rearrange the polynomial and write in standard form as

$f(x)=7x^5+2x^3-4x-12$

For the degree of the polynomial we see the highest exponent of the polynomial.

Degree = highest exponent

The highest exponent of the polynomial is 5.

Therefore, the degree of the polynomial is 5.

-Dominant- [34]3 years ago

4 0

IF f(x) = 2x3 + 7x5 − 4x − 12 << not written to standards
IS f(x) = 7x^5 +2x^3− 4x − 12 
x is to the 5th power 
then 5

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15 feet 10 inches is how many inches in all

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Answer:

190 inches

Step-by-step explanation:

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2 years ago

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3 years ago

In how many ways can a committee of 5 people be chosen from a total of 30 possible people?

Stolb23 [73]

Answer: 142506

Step-by-step explanation:

Given : The total number of choices for people in committee = 30

The number of people need to be chosen =5

Since , here order doesn't matter, so we use combination.

The combination of r things taking from n at a time is given by :-

$C(n,r)=\dfrac{n!}{(n-r)!r!}$

Now, the number of possible combinations of 5 people be chosen from a total of 30 possible people :-

$C(30,5)=\dfrac{30!}{(30-5)!5!}\\\\=\dfrac{30\times29\times28\times27\times26}{120}\\\\=142506$

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3 0

2 years ago

What are the solutions of the quadratic equation? Solve by factoring. 4x^2-18x+20=0

Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

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3 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

3 years ago