Answer: 21.00
Step-by-step explanation: 48-27 = 21
9514 1404 393
Answer:
- P₂ and x are both supplementary to N₁
- Q₁
- R = 90° -x
- ΔSMP ≅ ΔSMR ∴ PS ≅ SR
Step-by-step explanation:
1. Angles P₂ and N₁ are opposite angles of inscribed quadrilateral PMNQ, so are supplementary. Angles N₁ and N₂ form a linear pair, so are supplementary. Angles supplementary to the same angle (N₁) are congruent, hence P₂ = x ≅ N₂
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2. ΔPMQ is isosceles, so angle Q₁ is also congruent to x.
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3. In ΔPMQ, the sum of angles is 180°, so ...
M₁ +2x = 180°
Dividing by 2 gives ...
M₁/2 +x = 90°
Angle M₁ subtends arc PQ of circle M. Angle R inscribed in circle M subtends the same arc, so ...
R = (M₁/2)
R = 90° -x
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4. From the above, we know that angles N₂ and R are complementary (total 90°), so angle S₂ = 90°. Segment MS will only intersect chord PR at right angles at the midpoint of that chord.
Hence S is the midpoint of PR and PS = SR.
Answer : The different is, find BC - AC and find AC + CB, find AB and find CA + BC are same.
Step-by-step explanation :
As see that, AB is a line segment in which point C is represented in between the line.
As we are given that:
AC = 3
CB = 7
So,
AC + CB = 3 + 7 = 10
Similarly,
CA + BC = 3 + 7 = 10
Similarly,
AB = AC + CB = 3 + 7 = 10
But,
BC - AC = 7 - 3 = 4
From this we conclude that, find AC + CB, find AB and find CA + BC are same things while find BC - AC is a different thing.
Hence, the different is, find BC - AC and find AC + CB, find AB and find CA + BC are same.
Well to find the range, you need to take the highest number and subtract the lowest from it:
3 - -97
3 + 97
100
Range is always positive
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