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Shtirlitz [24]
3 years ago
15

A six dice is rolled 150 times.Which of the following best describes how many times it is likely to land on a odd number

Mathematics
1 answer:
AlladinOne [14]3 years ago
3 0

Answer:

approximately 75 times i think lol

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Can sumbody help meh wit dis plz and ty .I’ll give ya 14 points
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Answer:

1. is 5  

2. is -4

3. is -24

Step-by-step explanation:

i dont understand why you didnt just use a calculator but here.

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According to this line plot, 3 players on this team each had 15 strikeouts for a total of 45 strikeouts. How many strikeouts did
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The formula of pyramid is 1/3 Bh where B is area of base and h is height.

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3 years ago
PLEASE I NEED HELP ON THIS T^T
nignag [31]

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10

Step-by-step explanation:

we can solve this using basic algebra

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3 years ago
PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie
Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

3 0
3 years ago
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