Question

If f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3, fine (f-g)(x)

Answer 1

Answer:

$\large\boxed{(f-g)(x)=-3x^2-x-4}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)$

$f(x)=-4x^2-6x-1,\ g(x)=-x^2-5x+3\\\\(f-g)(x)=(-4x^2-6x-1)-(-x^2-5x+3)\\\\(f-g)(x)=-4x^2-6x-1-(-x^2)-(-5x)-3\\\\(f-g)(x)=-4x^2-6x-1+x^2+5x-3\qquad\text{combine like terms}\\\\(f-g)(x)=(-4x^2+x^2)+(-6x+5x)+(-1-3)\\\\(f-g)(x)=-3x^2-x-4$