I think the answer is that what i think
Answer:
There are 10 counters in the bag and you want the 4
As their is only one for the probability is
1/10
There are now 9 counters left in the bag.
You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)
There are only four even counters in the bag of nine counters so the probability is
4/9
As you want both of these to occur, you need to multiply them
1/10 x 4/9 = 49/90
Step-by-step explanation:
Answer:
Step-by-step explanation:
As per given information there are 18000 CCTV cameras in the area of 783.8 square kilometers
To find the average number of cameras you divide the number by the area.
The average number of CCTV cameras per square kilometer in NYC = 18000/783.8 = 22.9650421026 ≈ 23
It should be rounded up if taking approximate number
Yes you can have as many equal signs as you need and the approximately equal sign in the same equation.
is the inequality that describes this problem
<h3><u>Solution:</u></h3>
Given that Travis can spend no more than $125.75 every month
To find: linear inequality that describes the problem
Let the amount spent on movies = x dollars
Given that Travis decided to spend 4.3 times as much money on video games as he spends on movies
Amount spent on video games = 4.3 (amount spent on movies)
Amount spent on video games = 4.3x
Travis can spend no more than $125.75. That is, he can spend less than or equal to $125.75
<em><u>Thus, the inequality representing the situation is:</u></em>


Thus the required inequality is found
228 - 48 = 180
180/48 = 3.75
Its increase 375%