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Nataly [62]
3 years ago
8

What is 5x+10=2x-5=180

Mathematics
2 answers:
kozerog [31]3 years ago
5 0
Answer: 34
5 times 34=170
170+10=180
katrin2010 [14]3 years ago
3 0

Answer: x=-5

<u>Move all terms to the left</u>

<u></u>5x+10-(2x-5)=0<u></u>

<u></u>

<u>Get rid of parentheses</u>

<u></u>5x-2x+5+10=0<u></u>

<u></u>

<u>Add all the numbers together, and all the variables</u>

<u></u>3x+15=0<u></u>

<u></u>

<u>Move all terms containing x to the left, all other terms to the right </u>

<u></u>3x=-15\\x=-15/3\\x=-5<u></u>

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Find the 91st term of the arithmetic sequence 28, 8, -12, ...
lesya692 [45]

Answer:

Step-by-step explanation:

The explicit formula for an arithmetic sequence is

a_n=a_1+d(n-1)

where n is the position of the number in the sequence, a1 is the first number in the sequence, and d is the common difference between the numbers.  

If we are looking for the 91st term, our n = 91;

our a1 is 28, and

the common difference is -20.  Putting all that together gives us the explicit formula for this sequence:

a_{91}=28-20(91-1) and

a_{91}=28-20(90) and

a_{91}=28-1800 so

a_{91}=-1772

3 0
4 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

Since b^2 -4ac = 256 we have 2 real distinct root roots

Step-by-step explanation:

4x^2+12x=7

We need to subtract 7 to get it in the proper form

4x^2+12x-7=7-7

4x^2+12x-7=0

The discriminant is b^2 -4ac

when the equation is ax^2 +bx+c

so a =4   b=12 and c=-7

(12)^2 - 4(4)(-7)

144 +112

256

If b^2 -4ac > 0 we have 2 real distinct roots

If b^2 -4ac = 0 we have one real root

If b^2 -4ac < 0 we have two complex root

Since b^2 -4ac = 256 we have 2 real distinct root roots

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3 years ago
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aivan3 [116]
1)

4m^4 - 5m^2

answer is D. last choice

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Answer:

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Step-by-step explanation:

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Hence, there are a total of 4 cubes with one face painted.

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4 years ago
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It's C : sinA = h/c
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4 years ago
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