Scrieți un program care citește un număr natural n și determină suma cifrelor divizibile cu 3 ale lui n.

Help with some questions. Thank you!

Oksana_A [137]

Answer:

1. E: II and III only

2. A: (int)(Math.random() * (upper − lower) ) + lower

3. A: The value of answer is N

4. E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

5. C: 21

Explanation:

1. Which of the following is equivalent to while(userGuess != secretNumber)?

I. while( userGuess < secretNumber && userGuess > secretNumber)

NO - This will test until the userGuess is smaller AND greater than the secretNumber, at the same time... so that condition will never be true.

II. while( userGuess < secretNumber || userGuess > secretNumber)

YES - This will test the value of userGuess and see if it's smaller OR greater than secetNumber. So, it will loop until the user guesses right.

III. while( !(userGuess == secretNumber) )

YES, this will negate the match with the secretNumber. In order words, if it's not a match, it will return true... so the loop will run until it finds a false condition (a match).

As you can see, only II and III are valid.

2. If the lower limit were inclusive and the upper limit exclusive, which expression would properly generate values for the secret number?

A: (int)(Math.random() * (upper − lower) ) + lower

Since the lower limit is INCLUSIVE, we mustn't add one to the lower limit. Also, the Math.random() function returns a value that matches our needs; it returns a value between [0,1[ (meaning the 0 is included, but not the 1).

Assuming the (int) caster does return only the integer portion doing a round down of the result, we'll be perfect.

3. What conclusion can be made about the state of the program when the while loop terminates?

while(!answer.equals( "N"))

{.....

A: The value of answer is N

The condition in the loops reads as "While the negation of the answer being 'N', loop". If the answer equals 'N' then the method should return true... which will be negated by the '!' operator, causing the condition to be false. Thus we know that if the loop ends, the value of answer contains 'N', any other value will keep the loop going.

4. Assuming numGuesses is initialized to 1, how would the while statement be modified to include an extra criterion limiting the number of guesses to 15?

E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

This modified condition will first test to see if the user has guessed the secretNumber (if he has, the first sub-parenthesis will be true... so the left side of the && operator will be false due to the negation operator. The right side of the && operator will check to see how many tries have been attempted. Since the counter starts at 1, it needs to go up to 15 inclusively... so the <= is the right comparison operator.

5. After execution of the following code segment, what will be displayed?

int x = 1;

while(x < 18)

{

x += 5;

}

System.out.println(x);

C: 21

The x variable is initialized with 1... then enters the loop, in which it is incremented by 5 at each passage.

So after first passage, x = 6

After second passage, x = 11

After third passage, x = 16

After fourth passage, x = 21

Cannot enter the loop again because 21 > 18.

So, it will print out the value of 21.

3 0

3 years ago

Write a C program to implement a command called displaycontent that takes a (text) file name as argument and display its conte

Zanzabum

Answer:

/*

Student: Hugo Meza

Date: February 15, 2019

Description: This program mimic the cat command from Linux. Checks whether the source file

has the right permissions, and then writes in the console its content.

*/

#include <stdio.h>

#include <fcntl.h>

#include <unistd.h>

#include <errno.h>

int hasPermission(char *filepath){

int returnval;

// Check file existence

returnval = access (filepath, F_OK);

if(errno == ENOENT){

printf ("%s does not exist\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n", filepath);

return 0;

}

// Check read access

returnval = access (filepath, R_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

// Check write access

returnval = access (filepath, W_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

return 1;

}

int main(int argc, char* argv[]){

if(!argv[1]){

printf("Error. Specify file to open\n");

return 0;

}

int fd;

char *fp = argv[1], content[fd];

if(hasPermission(fp) == 0)

return 1;

fd = open(fp, O_RDONLY);

int bytes = read(fd,content,sizeof(content)-1);

write(1, content, bytes);

close(fd);

return 0;

}

Explanation:

7 0

3 years ago

William found out that someone used his report on American culture without his permission. What is William a victim of?

Mnenie [13.5K]

He is a victim of plagiarism.

Plagiarism is when someone steals someone else's work, to help benefit themselves. Taking credit for the other person work.

Hope this helps!

3 0

3 years ago

Read 2 more answers

write a c++program that allows the user to enter the last names of fivecandidates in a local election and the number of votes re

madreJ [45]

Answer:

#include<iostream>

#include<stdlib.h>

using namespace std;

int main(){

//initialization

string str1[5];

int arr_Vote[5];

int Total_Vote=0,max1_Index;

int max1=INT_MIN;

//loop for storing input enter by user

for(int i=0;i<5;i++){

cout<<"Enter the last name of candidate: "<<endl;

cin>>str1[i];

cout<<"Enter the number of vote receive by the candidate: "<<endl;

cin>>arr_Vote[i];

//calculate the sum

Total_Vote = Total_Vote + arr_Vote[i];

//find the index of maximum vote

if(arr_Vote[i]>max1){

max1=arr_Vote[i];

max1_Index=i;

}

//display

cout<<"\nThe output is......"<<endl;

//loop for display data of each candidate

for(int i=0;i<5;i++){

cout<<str1[i]<<"\t"<<arr_Vote[i]<<"\t" <<float(arr_Vote[i]*100)/Total_Vote<<"%"<<endl;

}

//display winner

cout<<"The winner candidate is"<<endl;

cout<<str1[max1_Index]<<"\t"<<arr_Vote[max1_Index]<<"\t"<<float(arr_Vote[max1_Index]*100)/Total_Vote<<" %"<<endl;

}

Explanation:

Create the main function and declare the two arrays and variables.

the first array for storing the names, so it must be a string type. second array stores the votes, so it must be int type.

after that, take a for loop and it runs for 5 times and storing the values entered by the user in the arrays.

we also calculate the sum by adding the array data one by one.

In the same loop, we also find the index of the maximum vote. take an if statement and it checks the element in the array is greater than the max1 variable. Max1 variable contains the very small value INT_MIN.

If condition true, update the max1 value and update the max1_Index value.

The above process continues for each candidate for 5 times.

After that, take a for loop and display the data along with percentage by using the formula:

$Vote\,percent=\frac{Vote\,receive*100}{Total\,vote}$