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Anika [276]
2 years ago
8

To create a datetime object for the current date and time, you can use theGroup of answer choicestoday() method of the date clas

stoday() method of the datetime classnow() method of the date classnow() method of the datetime class
Computers and Technology
1 answer:
SVEN [57.7K]2 years ago
6 0

var theDate = new DateTime (DateTime.Today.Year, DateTime.Today.Month, DateTime.Today.Day, hours, minute, second);

You might be interested in
Write a function chat accepts a pointer to a C-string as its argument. The function should count the number of vowels appearing
Dovator [93]

Answer:

Function contains into the code asked for:

  • Receives a string as an argument.  
  • count the number of vowels in the string and return that number.
  • receives a string as an argument.
  • count the number of consonants in the string and return that number.  

Explanation:

//Let's call libraries

#include <stdio.h>  

#include <conio.h>

//Start main

int main()

{

//*Declare functions for counting number of vowels and consonants

int vowels=0;      

int consonants=0;    

int all=0;    

//Output need information

//Ask user to input a string

printf("what do you want to count?\n");    

printf("1-the vowels.\n");      

printf("2-the consonants.\n");    

printf("3-all of the letters on a phrase.\n");      

printf("\n");      

printf("-> ");      

int a;    

a = getchar();

   switch (a)

   {          

//Ask user what function they want to run

case '1':

//Call the function needed to count the vowels  

            printf("Introduce a phrase: ");                  

char textoa[1001];                

scanf("%s", &textoa);

char *p;                  

p = textoa;                

while (*p != '\0')

               {

                     if (*p == 'a' || *p == 'e' || *p == 'i' || *p == 'o' || *p == 'u' || *p == 'A' || *p == 'E' || *p == 'I' || *p == 'O' || *p == 'U') vocales ++;

                     p++;

               }

               printf("there are %d vowels.", vowels);                  

break;            

case '2':

//Call the function needed to count the consonants

printf("Introduce a phrase: ");                

char textob[1001];                

scanf("%s", &textob);

p = textob;                

while (*p != '\0')

               {

                     if (*p == 'b' || *p == 'B' || *p == 'c' || *p == 'C' || *p == 'd' || *p == 'D' || *p == 'f' || *p == 'F' || *p == 'g' || *p == 'G' || *p == 'h' || *p == 'H' || *p == 'j' || *p == 'J' || *p == 'k' || *p == 'K' || *p == 'l' || *p == 'L' || *p == 'm' || *p == 'M' || *p == 'n' || *p == 'N' || *p == 'p' || *p == 'P' || *p == 'q' || *p == 'Q' || *p == 'r' || *p == 'R' || *p == 's' || *p == 'S' || *p == 't' || *p == 'T' || *p == 'v' || *p == 'V' || *p == 'w' || *p == 'W' || *p == 'x' || *p == 'X' || *p == 'y' || *p == 'Y' || *p == 'z' ||  

*p == 'Z') consonants ++;

                     p++;

               }

               printf("there are %d consonants.", consonants);                  

break;            

case '3':

printf("Introduce a phrase: ");                

char textoc[1001];                

scanf("%s",&textoc);

p = textoc;                

while (*p != '\0')

               {

                     if (*p == 'a' || *p == 'e' || *p == 'i' || *p == 'o' || *p == 'u' || *p == 'A' || *p == 'E' || *p == 'I' || *p == 'O' || *p == 'U' || *p == 'b' || *p == 'B' || *p == 'c' || *p == 'C' || *p == 'd' || *p == 'D' || *p == 'f' || *p == 'F' || *p == 'g' || *p == 'G' || *p == 'h' || *p == 'H' || *p == 'j' || *p == 'J' || *p == 'k' || *p == 'K' || *p == 'l' || *p == 'L' || *p == 'm' || *p == 'M' || *p == 'n' || *p == 'N' || *p == 'p' || *p == 'P' || *p == 'q' || *p == 'Q' || *p == 'r' || *p == 'R' || *p == 's' || *p == 'S' || *p == 't' || *p == 'T' || *p == 'v' || *p == 'V' || *p == 'w' || *p == 'W' || *p == 'x' || *p == 'X' || *p == 'y' || *p == 'Y' || *p == 'z' || *p == 'Z') all ++;

                     p++;

               }

               printf("there are %d letters on the phrase.", all);                 break;

   }     getch();

}

8 0
3 years ago
How do i move a file in python3
Levart [38]

Answer:

To move a file in Python, we will need to import the os and shutil modules that provide us the ability to copy, move, and remove files in Python. Both of these modules provide methods to do so, although in many cases the shutil module has more convenient methods.

Keep in mind that the destination directory needs to exist in order for this example to work. Once you've set up the directories "d1" and "d2" (or just changed the example to fit your directory structure), run the code. Now check out the "d2" directory and you should see the xfile.txt if now present in that directory.

6 0
3 years ago
Write a program to read from std_info.txt.
slavikrds [6]

Answer:

import pandas as pd

# loads the text file as a pandas dataframe

student_file = pd.read_fwf("std_info.txt")

# opens a new text file if the student_avg does not exist

# the file closes automatically at the end of the with statement

with open('student_avg.txt', 'w+') as file:

   for row in student_file.iterrows():

       file.write(row)

   ee = student_file[student_file['major'=='EE']]

   cpe = student_file[student_file['major'=='CPE']]

   file.write(f'EE average = {ee['EE'].mean()}')

   file.write(f'CPE average = {ee['CPE'].mean()}')

   file.write(f'Total average = {student_file['EE'].mean()}')

Explanation:

The python program gets the text file as a fixed-width file and loads the file as a pandas dataframe. The dataframe is used to get the total average GPA the student GPA and the average GPA of students in various departments. The results are saved in a new file called 'student_avg.txt'.

6 0
3 years ago
How can you solve real world mathematical problems using two linear equations in two variables​
ipn [44]

Answer:

import numpy as np

a = int(input ("Enter a"))

b = int(input ("Enter b"))

c = int(input ("Enter c"))

d = int(input ("Enter d"))

c1 = int(input ("Enter c1"))

c2 = int(input ("Enter c2"))

array1 =[[a, b],[c, d]]

A = np.array (array1)

B = np.array ([c1, c2])

X = np.linalg.inv (A).dot (B)

print (X)

Explanation:

let ax + by =c1

     cx + dy =c2

We have used the above NumPy library that has the methods for matrix calculation, and here we have used matrix multiplication, and the inverse of a matrix to find the value of x and y.

We know AX=B

X = inv A. B

And this we have used above. We can calculate inv A and do matrix multiplication using NumPy. And thus we get the above solution.

3 0
3 years ago
Can someone please please please help me!
vova2212 [387]
Is that apologetics?

5 0
3 years ago
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