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guapka [62]
3 years ago
8

Solve the system of linear equations by graphing. Check your solution.

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0
Without the graph the answer is (2,-1)
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Please help quarter ends tomorrow and I don’t know what to do I’m failing all my classes
Nutka1998 [239]

Step-by-step explanation:

x = -10, y = 10

y= -4x+4

m1×m2 = -1

-4 × m2 = -1

m2 = 1/4

y-y1 = m(x-x1)

y-10 = 1/4(x+10)

y-10 = 1/4x +10/4

(×4)

4y-40=x+10

4y=x+50

x-4y+50=0

3 0
3 years ago
Please solve quickly ​
Luba_88 [7]
The correct answer is 2.86
7 0
2 years ago
I need help finding my variable
Oksi-84 [34.3K]
The length is two times its width, and the perimeter equals 24. 

All the sides added up equal 24.

4 and 8 could be the width and the length of the rectangle.

4*2= 8 and

4+4+8+8= 24

width= 4 length= 8

I hope this helps!
~kaikers
8 0
3 years ago
Read 2 more answers
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
a store buys a jacket for$20.00 and then sells it for 80% more what is the selling price for the jacket
victus00 [196]
Answer: 100$.

100% - 80% = 20%

20$ / 0.20(20%) =100$
7 0
3 years ago
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