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shepuryov [24]
3 years ago
9

7. Joey wants to find the area of the parallelogram below.

Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

I'm not sure but I think it is b

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3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d
Alexxx [7]

Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

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3 years ago
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12345 [234]

Answer:

Figure 1

Step-by-step explanation:

Congruent shapes are shapes that share the same side lengths and angle measures. In figure 1, we see that all sides and angles are marked equal, thus both shapes are congruent. However, in figure 2, we clearly see that the sides of each of the triangles are different. Thus, the triangles in figure 2 are not congruent.

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Solve the inequality.<br> 2(4+2x)&gt;5x+5<br> oxs-2<br> O X2-2<br> xs3<br> x23
mafiozo [28]

For this case we must resolve the following inequality:

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8-5 + 4x> 5x\\3 + 4x> 5x

Subtracting 4x from both sides of the inequality:

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Answer:

x

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3 years ago
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Answers below

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emmainna [20.7K]

Answer:

-1,1

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because if you plot the points that is half.

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