a. 1^5 = 1 × 1 × 1 × 1 × 1 = 1
b. 2 × 2 × 2 × 2 × 2 = 2^5 = 32
c. 20^3 = 20 × 20 × 20 = 8.000
d. 7 × 7 × 7 × 7 = 7^4 = 2.401
3(4+n)=18+n
distribute
12+3n=18+n
minus n both sides
12+2n=18
minus 12 both sides
2n=6
divide by 2
n=3
the number is 3
equation is
3(4+n)=18+n
Answer:
f(5)=-1
Step-by-step explanation:
Solving for x would give me 14 and negative 10 which would lead to the problem looking like so 14(-10-4)=140
∠ABC = ∠CDA (given)
∠BCA = ∠DAC (given)
CA = AC (common side)
ASA congruence criterion = when two angles of two triangles are equal and their included side is also equal, we can consider those triangles to be congruent to each other.
Since two angles in triangle △ABC and△CDA are equal and since their included side is also equal we can conclude that they are congruent.
Therefore, △ABC ≅ △CDA under the ASA congruence criterion.
