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victus00 [196]
3 years ago
9

Consider the expression 150 + 150(2.5). Which statements are correct?

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0

Answer: E and D

Step-by-step explanation:

150 + 150(2.5) would be solved like this:

150 x 2.5 = 375

150 + 375 = 525

Margarita [4]3 years ago
5 0

Answer:

C D E is the answer

Step-by-step explanation:

i just know

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Find the equation of the line through point (−5,5) and perpendicular to y=59x−4
VARVARA [1.3K]

Answer:

Step-by-step explanation:

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2 years ago
What is 7/12 divided by 36?
Georgia [21]
7/12 = 0.84
0.84/36 = 0.0233·
3 0
3 years ago
Steve's scores on 6 of his tests were 92, 78, 86, 92, 95, and 91. If he took a seventh test and raised the mean of his scores by
monitta

Answer:

96

Step-by-step explanation:

First we need to know the mean of the Steve's scores on 6 of his tests. Given the six scores as 92, 78, 86, 92, 95, and 91.

Mean = sum of the scores/Total test taken

Mean = 92+78+86+92+95+ 91/6

Mean = 534/6

Mean = 89

If he took the seventh test and the mean score is raised by 1 them the new mean will be expressed as;

New mean = 92+78+86+92+95+ 91+x/7 = 89+1

Where x is the new score. Note that of a new score is added, the total year taken will also change to 7

To get x;

92+78+86+92+95+ 91+x/7 = 89+1

92+78+86+92+95+ 91+x/7 = 90

534+x/7 = 90

Cross multiply

533+x = 90×7

533+x = 630

x = 630-534

x = 96

Hence the score of the seventh test is 96

8 0
3 years ago
Find the distance between P1(1, -91°) and P2(3, 335°) on the polar plane.
Dmitrij [34]

Answer:

2.749

Step-by-step explanation:

Use the polar distance formula:

\sqrt{r_{1}^{2}+{r_{2}^{2}-2 r_{1} r_{2}cos(theta_{1} -theta_{2})

\sqrt{10^{2}+{3^{2}-2(1) (3)cos(225-(-91))

2.749

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3 years ago
Solve the inequality below for x. -3.2(2x-1) less than or equal to 17.6
zhenek [66]

- 3.2(2x - 1) \leqslant 17.6 \\  - 6.4x + 3.2 \leqslant 17.6 \\  - 6.4x \leqslant 14.4 \\ x \geqslant 2.25
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3 years ago
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