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victus00 [196]
3 years ago
9

Consider the expression 150 + 150(2.5). Which statements are correct?

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0

Answer: E and D

Step-by-step explanation:

150 + 150(2.5) would be solved like this:

150 x 2.5 = 375

150 + 375 = 525

Margarita [4]3 years ago
5 0

Answer:

C D E is the answer

Step-by-step explanation:

i just know

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Which of the statements are true about the function f given by f(x) = 100-e? Select all that apply.
tatiyna

From the above function, it is clear that the value of f is never 0. Hence the statement that is true is (Option E), See explanation of same below.

<h3>What is the explanation for the above function?</h3>

Note that the function is related to Euler's number which is depicted as:
e ≈ 2.7182. The function is given as:

f(x) = 100 * e^{-x}

Assuming x = -2, we'd have:

100 * 2.7182^{-2}

= 271.82^{-2}

= 0.00001353354

Hence, even when x tends < 0 the function f(x) thus, is never 0. See the attached graph for confirmation.

Learn more about functions at:

brainly.com/question/25638609

#SPJ1

6 0
2 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
Nikitich [7]

You are given that all three sides are equal. You also know that all three angles are also equal. Therefore since all three angles are equal and every triangle has 180 degrees, each angle is 180/3 = 60

So

7x - 3 = 60                     Add three to both sides

7x - 3 + 3 = 60 + 3        Combine

7x = 63                          Divide by 7

7x/7 = 63/7

x = 9                              And that's your answer.

3 0
3 years ago
HELP ASAP I NEED TO PASS THIS
ratelena [41]
I don’t think it’s c it is c
3 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
Round the following numbers and estimate the product 52.84x28
Alona [7]
50x30=1500 (this is an approximated rounded answer)
3 0
3 years ago
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